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tankabanditka [31]
1 year ago
6

An observation tower is 65m high. A support wire is attached to the tower 30m from the top. If the support wire and the ground f

orm an angle of 56 degrees, what is the length of the support wire, to the nearest tenth?
Mathematics
1 answer:
Ksju [112]1 year ago
5 0

The support wire is the hypotenuse of the right triangle formed. Therefore, the length of the support wire is 42.2 meters.

The situation forms a right angle triangle.

<h3>Right angle triangle</h3>

A right angle triangle has one of its angles as 90 degrees. The sides and angles can be found using trigonometric ratios.

Therefore, the height of the tower where the wire was attached is the opposite side of the triangle formed.

The wire was attached 30 m from the top. Hence, 65m - 30m = 35 m.

Therefore,

sin 56° = opposite / hypotenuse

sin 56° = 35 / x

The hypotenuse is the length of the support wire.

Therefore,

x = 35 / 0.82903757255

x = 42.2195416164

x = 42.2 m

learn more on right angle here: brainly.com/question/9495022

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Marvin counts six $5 bills. write each value that he counts. what pattern do you see in the one digits of the values he counts?
spin [16.1K]
Answer: If the number of bills counted is odd, the ones digit is 5; if the number of bills is even, the ones digit is 0.

Explanation

1) Simulate the counting of the bills:

number of bills counted          value              ones digit

1                                             5                         5

2                                             5 + 5 = 10           0

3                                             10 + 5 = 15         5

4                                             15 + 5 = 20         0

5                                              20 + 5 = 25        5

6                                              25 + 5 = 30        0

2) Pattern: you can see that the ones digit alreternate: 5, 0, 5, 0, 5, 0, ...

If the number of bills counted is odd the ones digit is 5, if the number of bills is even the ones digit is 0.
4 0
3 years ago
Can someone explain to me the steps how they got 2 √4^2+2x-3-2 from this question…
Naddik [55]

Step-by-step explanation:

with your square root symbol I never know what is inside the square root and what is possibly outside.

so, I can only guess and see what comes close.

f(x) = 2x² + x - 1

g(x) = sqrt(2x - 1) ??? is that so ?

h(x) = -2

2g(f(x)) + h(x)

g(f(x)) means that the whole f(x) expression is used as x in g(x).

the whole combined function is then

2×sqrt(2(2x² + x - 1) - 1) - 2

2×sqrt(4x² + 2x - 2 - 1) - 2

2×sqrt(4x² + 2x - 3) - 2

and if I am not mistaken, then this is the solution you mentioned at the beginning (if I try to read between the typos and missing info).

this is how people get to this.

do you understand it now ? or is there still something unclear ?

6 0
1 year ago
5x^2-2x=2<br>help plsmmm​
Yuki888 [10]

Answer:

Presumably you're solving for x here?  Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\

let's solve it.  First we'll multiply both sides by five, making the first term a perfect square:

25x^2 - 10x - 10 = 0\\

Now we'll add 11 to both sides:

25x^2 - 10x + 1 = 11\\

Which makes the left side a perfect square:

(5x - 1)^2 = 11

And now we can solve for x:

(5x - 1)^2 = 11\\\\5x - 1 =  \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86             x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46

7 0
2 years ago
Heeeeeeeeeeeeeeeeelp
mel-nik [20]

Answer:6hrs and &270

8hours and &360

9.5hours and&427.50

Step-by-step explanation:

8 0
2 years ago
The midpoint of RS is N(-4,1). One endpoint is S(0,-7). A) what are the coordinates of R B) what is the Length of RS to the near
lora16 [44]
A) The coordinates of R is (-8,9)
B) The length of RS to the nearest tenth of a unit is 17.9
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