Answer:
Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is
there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have
and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
![V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5B28x%2B%5Cfrac%7B1%7D%7Bx%7D%2Bxln%5E2x-12xlnx-6lnx%5D)
and by evaluating in the limits we have
Hope this helps
regards
Answer:
A. <u><em>X = 15</em></u> is the correct answer.
Step-by-step explanation:
It's the only one that really makes sense.
Hope this helped :)
Answer:
0.5 or 50%
Step-by-step explanation:
For any given value of 'x' representing the time between arrivals of two customers. If 0 < x <120, then the cumulative distribution function is:
Therefore, the probability that the time between the arrivals of two customers will be more than 60 seconds is determined by:
The probability is 0.5 or 50%.
Answer:1331cm
Step-by-step explanation:vol=lbh
11*11*11cm=1331cm
We have that
(v+6)^2 = 324-----> I raise to 1/2 both members----> [(v+6)^2]^(1/2)=(324)^(1/2)[(v+6)]=(324)^(1/2)-------------> v+6=√324
v=√324-6---------> 18-6=12
v=12
the answer is v=12
