Question

Indicate the equation of the line through (2, -4) and having slope of 3/5.

Answer 1

Answer:

The equation of the line is:

           $y=\dfrac{3}{5}x-\dfrac{26}{5}$

Step-by-step explanation:

We are asked to find the equation of a line that pass through (2,-4)  and having a slope of 3/5.

We know that the equation of a line with slope m and passing through points (a,b) is:

                  $y-b=m(x-a)$

Here (a,b)=(2,-4) and m=3/5

Hence, the equation of line is:

$y-(-4)=\dfrac{3}{5}\times (x-2)\\\\i.e.\\\\y+4=\dfrac{3}{5}\times (x-2)\\\\i.e.\\\\y=\dfrac{3}{5}x-\dfrac{6}{5}-4\\\\i.e.\\\\y=\dfrac{3}{5}x-\dfrac{26}{5}$

Answer 2

Y = mx + b

y = 3/5(x) + b

-4 = 3/5(2) + b

-4 = -2.4 + b

b = -4 + 2.4

b = -1.6 (-8/5)

y = 3/5x - 8/5.