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3 years ago

Suppose an electronics manufacturer knows from previous data that 1% of

Mathematics

2 answers:

Shkiper50 [21]3 years ago

8 0

Answer:

It is not a binomial experiment because the random variable associated with this experiment is a Geometric random variable.

Step-by-step explanation:

For an experiment to be a binomial experiment the variable associated with the experiment has to be a binomial random variable.

A binomial random variable should satisfy the following conditions:

There should be a fixed known no. of trials
There should be only 2 outcomes of a trial i.e either success or failure
Trial results should be independent
Same probability for each trial success or failure

Now lets see what is the random variable in this experiment:

The Random variable would be X = no. of selections until a defective one is found.

X does not satisfy the first condition for a binomial variable itself as the no. of trials is not fixed and is unknown.

Hence X is not a binomial random variable.

Rather X is a Geometric random variable. If we consider finding a defective one as a success then the variable is defined as the no. of trials until a success is achieved. But a binomial random variable is defined by no. of successes in a fixed no. of trials.

Hence it is not a binomial experiment .

Korolek [52]3 years ago

7 0

Answer:

It is not a binomial experiment

Step-by-step explanation:

For an experiment to be a binomial, the variable associated with the experiment has to be a binomial random variable.

A binomial random variable should satisfy the following conditions:

1. There should be a fixed known number of trials .

2.There should be only 2 outcomes of a trial i.e. either success or failure

3. Trial results should be independent

4. Same probability for each trial success or failure

The Random variable in this experiment is X = no. of selections until a defective one is found.

Now here,X does not satisfy the first condition for a binomial variable itself as the no. of trials is not fixed and is unknown.

Hence X is not a binomial random variable.

So this experiment is not binomial experiment.

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Gala2k [10]

Answer:

Step-by-step explanation:

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3 years ago

How do you solve P = C+MC, for M??

uranmaximum [27]

P = C +MC
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3 years ago

40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS

patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

$40,\:10,\:\frac{5}{2},\:\frac{5}{8}$

A geometric sequence has a constant ratio 'r' and is defined by

$\:a_n=a_0\cdot r^{n-1}$

Computing the ratios of all the adjacent terms

$\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}$

The ratio of all the adjacent terms is the same and equal to

$r=\frac{1}{4}$

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

$a_1=40$

Therefore, the nth term is calculated as

$\:a_n=a_0\cdot r^{n-1}$

$a_n=40\left(\frac{1}{4}\right)^{n-1}$

Put n = 5 to find the next term

$a_5=40\left(\frac{1}{4}\right)^{5-1}$

$a_5=40\cdot \frac{1}{4^4}$

$a_5=\frac{40}{4^4}$

$=\frac{2^3\cdot \:5}{2^8}$

$a_5=\frac{5}{2^5}$

$a_5=\frac{5}{32}$

now, Put n = 6 to find the 6th term

$a_6=40\left(\frac{1}{4}\right)^{6-1}$

$a_6=40\cdot \frac{1}{4^5}$

$a_6=\frac{40}{4^5}$

$=\frac{2^3\cdot \:5}{2^{10}}$

$a_6=\frac{5}{2^7}$

$a_6=\frac{5}{128}$

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

$a_5=\frac{5}{32}$

$a_6=\frac{5}{128}$

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3 years ago

The sum of the differences must be zero for any distribution consisting of n observations.

Semenov [28]

Answer:

false

Step-by-step explanation:

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3 years ago

What's the answer??

baherus [9]

The first one: whole equation when move1 to the left, same with the second I believe

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3 years ago