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siniylev [52]
3 years ago
12

Suppose an electronics manufacturer knows from previous data that 1% of

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

It is not a binomial experiment because the random variable associated with this experiment is a Geometric random variable.

Step-by-step explanation:

For an experiment to be a binomial experiment the variable associated with the experiment has to be a binomial random variable.

A binomial random variable should satisfy the following conditions:

  1. There should be a fixed known no. of trials
  2. There should be only 2 outcomes of a trial i.e either success or failure
  3. Trial results should be independent
  4. Same probability for each trial success or failure

Now lets see what is the random variable in this experiment:

The Random variable would be X = no. of selections until a defective one is found.

X does not satisfy the first condition for a binomial variable itself as the no. of trials is not fixed and is unknown.

Hence X is not a binomial random variable.

Rather X is a Geometric random variable. If we consider finding a defective one as a success then the variable is defined as the no. of trials until a success is achieved. But a binomial random variable is defined by no. of successes in a fixed no. of trials.

Hence it is not a binomial experiment .

Korolek [52]3 years ago
7 0

Answer:

It is not a binomial experiment  

Step-by-step explanation:

For an experiment to be a binomial, the variable associated with the experiment has to be a binomial random variable.

A binomial random variable should satisfy the following conditions:

1. There should be a fixed known number of trials .

2.There should be only 2 outcomes of a trial i.e. either success or failure

3. Trial results should be independent

4. Same probability for each trial success or failure

The Random variable in this experiment is X = no. of selections until a defective one is found.

Now here,X does not satisfy the first condition for a binomial variable itself as the no. of trials is not fixed and is unknown.

Hence X is not a binomial random variable.

So this experiment is not  binomial experiment.

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In the diagram of parallelogram HIJK below, the diagonals HJ and IK are perpendicular, as shown. If HJ is 10 inches long and IK
guapka [62]

Answer:

It is the hypotenuse of a right triangle with legs 5 and 12.

Step-by-step explanation:

The diagonals of a parallelogram bisect each other. If the angle at which they meet is a right angle, then a right triangle is formed whose legs are half the length of each of the diagonals, and whose hypotenuse is the length of one side of the parallelogram (rhombus).

Here, the triangle's leg lengths are 5 and 12, so the Pythagorean theorem tells us the hypotenuse is ...

  √(5²+12²) = √(25+144) = √169 = 13

Since the perpendicular diagonals are 10 and 24 inches long, the side length of the rhombus must be 13 inches long.

HK must be 13 inches because the Pythagorean theorem applies and that's what it says.

3 0
4 years ago
Answer question 10( I do not understand stand it)
omeli [17]
You would have to plot the vertices and play a sort of game of connect the plots ( *Or connect the dots but more literally, the plots*) Then decide whether or not your final illustrations have the potential to be similar. If so, why?

EXAMPLE ANSWER: DO NOT USE ANY IF THEM BELOW FOR I DO NOT KNOW THE UNIT LENGTH OR SHAPE THE CONNECTED DOTS WOULD CREATE!!!

The two triangles could be similar due to the identical amount of units between each vertice. Furthermore, you could connect the units in a certain orientation, keeping the units in mind, and produce two identical triangles.

Or...

The two triangles could be similar due to the type of triangle. Each triangle has the potential to be a (right/scalene/isosceles/obtuse/acute, etc).
5 0
4 years ago
Find the length of side x in simplest radical form with a rational denominator.
galben [10]
<h2>Answer</h2>

x =  \frac{7 \sqrt{3} }{2}  \\

<h2>Explain</h2>

.

\frac{7}{x}  =  \frac{2}{ \sqrt{3} }  \\

7 \times  \sqrt{3}  = 2 \times x

7 \sqrt{3}  = 2x

\frac{7 \sqrt{3} }{2}  = x \\

x =  \frac{7 \sqrt{3} }{2}  \\

.

.

#LearnWithBrainly

<h2>GAK BISA BAHASA INGGRIS</h2>
3 0
3 years ago
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