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Kazeer [188]
3 years ago
7

What is the value of X ?

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
x^2+12^2=13^2\\\\ x^2+144=169 \ |-144 \\\\ x^2=25 \\\\ x=\sqrt{25} \\\\ x=5
or
x^2+12^2=13^2\\\\ x=\sqrt{13^2-12^2}=\sqrt{25}=5
Rainbow [258]3 years ago
7 0
X = 5. Using the pythagreom theorem, a²+b²=c², to solve x we put in the numbers into the equation getting a²+12²=13². Then solve for a. a²=25, 5·5=25, a=5 which means x=5.
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What is the solution to the inequality below?
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Fastest and easiest way to do this is to graph the inequality and find out the lines.

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3 years ago
Amelia launched her science fair rocket, and then backed away. The path of the rocket is given by the equation below, where y is
Mamont248 [21]

Answer:

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2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  

                y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

             \frac{dy}{dx} = -2( 2x) +5(1) =  -4x +5

Equating zero

            \frac{dy}{dx} = 0

⇒      -4 x +5 =0

⇒      -4 x = -5

⇒          x = \frac{5}{4}

<em> The rocket hit the ground at     </em>x = \frac{5}{4}<em></em>

<u><em>Step(ii):</em></u>-

    \frac{dy}{dx}  =  -4x +5  ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

 \frac{d^{2} y}{dx^{2} }  = - 4(1)

The maximum height at x = \frac{-5}{4}

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y = \frac{-2(25)+ 25 (16)+7(64)}{64}

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<em>The maximum height of the rocket = 12.468 feet</em>

       

4 0
3 years ago
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Gekata [30.6K]

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Concept:

From the given graph, we can see that it is an isosceles triangle since the two base angles are congruent.

In geometry, an isosceles triangle is a triangle that has two sides of equal length.

If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.

Solve:

<u>Given information</u>

First Side = 7

Second Side = x + 14

<u>Given expression deducted from the definition of an isosceles triangle</u>

Second Side = First Side

<u>Substitute values into the expression</u>

x + 14 = 7

<u>Subtract 14 on both sides</u>

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\boxed{x=-7}

Hope this helps!! :)

Please let me know if you have any questions

5 0
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Help! Please explain I have a test tomorrow !
Fofino [41]
<h3>given:</h3>

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<u>answer</u><u>=</u><u> </u><u>option</u><u> </u><u>D</u>

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