Question

What is the value of X ?

Answer 1

$x^2+12^2=13^2\\\\ x^2+144=169 \ |-144 \\\\ x^2=25 \\\\ x=\sqrt{25} \\\\ x=5$
or
$x^2+12^2=13^2\\\\ x=\sqrt{13^2-12^2}=\sqrt{25}=5$

Answer 2

X = 5. Using the pythagreom theorem, a²+b²=c², to solve x we put in the numbers into the equation getting a²+12²=13². Then solve for a. a²=25, 5·5=25, a=5 which means x=5.