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MariettaO [177]
4 years ago
13

Why do wee see lightning before we hear thunder?

Physics
2 answers:
IrinaK [193]4 years ago
7 0
Lightning travels at a speed of 300,000,000 meters per second, which is about 186,000 miles per second. The speed of sound, in dry air, is about 1 mile every 5 seconds. Since dry air is not common during a thunderstorm, the speed at which thunder travels is only an approximation, but a rough calculation can still be made of the distance of a thunderstorm by comparing the time factors of lightning and its accompanying thunder. Because the speed of light is so fast, the travel time for lightning in the case of a thunderstorm's relatively close distance can be considered instantaneous. Thus, counting the elapsed time in seconds between the flash of lightning and the following thunder, and then dividing that number by 5, will provide the distance in miles. If, for example, 10 seconds pass between the lightning and the thunder, the storm is 2 miles away.
Arlecino [84]4 years ago
3 0
Once then light is gone the air collapses back in and creates a sound wave that we hear<span> as </span>thunder<span>. The reason </span>we see lightning before we hear thunder<span> is because light travels faster than sound!

that is  why 

i hope my answer helped you</span>
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allsm [11]

Answer:

The percentage is  k = 12.5 \%

Explanation:

From the question we are told that

    The  axis is is  at  \theta =  45 ^o

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                I_{1} =  \frac{I_o}{ 2}

Where  I_o is the intensity of unpolarized light

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         I_2  = I_ 1 * cos ^2(\theta )

         I_2  = \frac{I_o}{2}  * cos ^2(45 )

        I_2  = \frac{I_o}{2} *  \frac{1}{2}  =  \frac{I_o}{4}

  Now the light emerging from the third  polarizer is mathematically represented as      

       I_3  = I_ 2 * cos ^2(\theta )

       I_3  = \frac{I_o}{4}   * cos ^2(45 )

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Now the percentage of the intensity of light that emerged with respect to the intensity of  the unpolarized light is

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