1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xeze [42]
2 years ago
11

Please answer this fast I 'll marks them brainliest answer ​

Physics
1 answer:
Reptile [31]2 years ago
8 0

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

You might be interested in
Are electrons lower in mass than neutrons
tamaranim1 [39]

Answer:

ya I just looked it up on Google

3 0
3 years ago
Read 2 more answers
An astronaut has a mass of 50.0 kg on earth. what is her mass on the moon, where gravity is 1 6 that on earth?
never [62]

I believe the correct gravity on the moon is 1/6 of Earth. Take note there is a difference between 1 6 and 1/6.

HOWEVER, we should realize that the trick here is that the question asks about the MASS of the astronaut and not his weight. Mass is an inherent property of an object, it is unaffected by external factors such as gravity. What will change as the astronaut moves from Earth to the moon is his weight, which has the formula: weight = mass times gravity.

<span>Therefore if he has a mass of 50 kg on Earth, then he will also have a mass of 50 kg on moon.</span>

6 0
3 years ago
Help with 7,8,9 please!!
Marysya12 [62]

# 7 the answer is 4) because you need opposites in order to attract

# 8 I'm going to guess it is 4) because electricity is needed in order a light bolt to work.(don't take my word for this one I'm not sure but, the other answer are correct)

# 9  the answer is 4) because the comb dose collect negative charges from the hair in order to make the hair have positive charge.


Hope this helped : )

4 0
2 years ago
What is the current
Art [367]

Answer:

2.5mA

Explanation:

In the picture.

I think it's a clear.

8 0
2 years ago
charge, q1 =5.00μC, is at the origin, a second charge, q2= -3μC, is on the x-axis 0.800m from the origin. find the electric fiel
IRISSAK [1]

Answer:

Explanation:

Electric field due to charge at origin

= k Q / r²

k is a constant , Q is charge and r is distance

= 9 x 10⁹ x 5 x 10⁻⁶ / .5²

= 180 x 10³ N /C

In vector form

E₁ = 180 x 10³ j

Electric field due to q₂ charge

= 9 x 10⁹ x 3 x 10⁻⁶ /.5² + .8²

= 30.33 x 10³ N / C

It will have negative slope θ with x axis

Tan θ = .5 / √.5² + .8²

= .5 / .94

θ = 28°

E₂ = 30.33 x 10³ cos 28 i - 30.33 x 10³ sin28j

= 26.78 x 10³ i - 14.24 x 10³ j

Total electric field

E = E₁  + E₂

= 180 x 10³ j +26.78 x 10³ i - 14.24 x 10³ j

= 26.78 x 10³ i + 165.76 X 10³ j

magnitude

= √(26.78² + 165.76² ) x 10³ N /C

= 167.8 x 10³  N / C .

3 0
3 years ago
Other questions:
  • Dizziness. Our balance is maintained, at least in part, by the endolymph fluid in the inner ear. Spinning displaces this fluid,
    15·1 answer
  • PLS PLS PLS PLS PLS HELP
    6·1 answer
  • A wave is a disturbance that transfers energy through medium from one place to another.  Do the particles in the medium travel w
    11·1 answer
  • Tech A says that an overdrive gear ratio means the input gear turns faster than the output gear. Tech B says that overdrive rati
    7·1 answer
  • Select all that apply.
    11·2 answers
  • A 64 kg cross-country skier glides over snow. Thecoefficient
    11·1 answer
  • A projectile is shot horizontally at 23.4 m/s from the roof of a building 55.0 m tall. (a) Determine the time necessary for the
    6·1 answer
  • You are building a uniform to protect workers from all types of nuclear radiation. If you use material that blocks _____ radiati
    5·1 answer
  • After students complete a scientific investigation, why is it important for the class to discuss the results obtained by each la
    15·1 answer
  • What is the motion of an apple when it falls from a tree ? a)Constant b)accelerating c)decelerating d)zero​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!