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zimovet [89]
3 years ago
10

Explain the Construction of the mercury barometer ​

Physics
1 answer:
boyakko [2]3 years ago
6 0

Answer:

The basic construction, unchanged since Torricelli's experiment in 1643, is a glass tube about three feet long, closed at one end, filled with mercury, and inverted with the open end immersed in a cistern of mercury.

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100 N
weqwewe [10]

Answer:

The force required to move the cart is divided by three or 33.33 N.

Explanation:

8 0
3 years ago
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Two golf balls with the same mass were hit at the same time. Golf ball A went a shorter distance than golf ball B. What could be
Firdavs [7]

Answer:

Golf ball A was hit with a weaker force

Explanation:

Golf ball B went a larger distance than golf ball A, so we could think friction affected golf ball A rather than golf ball B. That is why the first two choices are wrong.

The strongest forced applied made golf ball B go further.

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3 years ago
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In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a sp
zvonat [6]

Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

<u>t = 13.43 s</u>

6 0
3 years ago
A man exerts a force of 180 N on a cart at an angle of 29° above the horizontal.
TiliK225 [7]
Answer:
This explanation from Physics/Geometry
60o |
|
| Fy (the vert. comp.)
↑
← 30o |
Fx (the horizontal componenet)

F = √(Fx2 + Fy2)
Fy = 50 · cos 60o = 50 · (1/2) = 25 N
Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N
I see, that vector sign did not appear in my comment above, so the vector equation is
→ → →
F = 50 cos 30o i + 50 cos 60o j
Explanation:
7 0
3 years ago
A fuzzy bunny sees a butterfly and chases it right off of a 20 m high cliff at 7m/s
bogdanovich [222]

A) 2.02 s

To find the time it takes for the bunny to reach the rocks below the cliff, we just need to analyze its vertical motion. This motion is a free fall motion, which is a uniformly accelerated motion. So we can use the suvat equation:

s=u_y t+\frac{1}{2}at^2

where

s is the vertical displacement

u is the initial vertical velocity

a is the acceleration

t is the time

For the bunny here, choosing downward as positive direction,

u_y = 0 (initial vertical velocity is zero)

s = 20 m

a=g=9.8 m/s^2 (acceleration of gravity)

And solving for t, we find the time of flight:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

B) 14.1 m

For this part, we need to consider the horizontal motion of the bunny.

The horizontal motion of the bunny is a uniform motion with constant velocity, which is the initial velocity of the bunny:

v_x = 7 m/s

Therefore the distance covered after time t is given by

d=v_x t

And substituting the time at which the bunny hits the ground,

t = 2.02 s

We find how far the bunny went from the cliff:

d=(7)(2.02)=14.1 m

C) 21.0 m/s at 70.5^{\circ} below the horizontal

The horizontal component of the velocity is constant during the entire motion, so it will still be the same when the bunny hits the ground:

v_x = 7 m/s

Instead, the vertical velocity is given by

v_y = u_y +at

And substituting t = 2.02 s, we find the vertical velocity at the moment of impact:

v_y = 0+(9.8)(2.02)=19.8 m/s

So, the magnitude of the final velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{7^2+(19.8)^2}=21.0 m/s

And the angle is given by

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{19.8}{7})=70.5^{\circ}

below the horizontal

5 0
3 years ago
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