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kari74 [83]
3 years ago
12

Find the charge q(t) on the capacitor and the current i(t) in the given lrc-series circuit. l = 5 7 h, r = 10 ω, c = 1 70 f, e(t

) = 1400 v, q(0) = 0 c, i(0) = 0 a

Physics
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

Explanation:

In this question, we are asked to calculate the value of q(t) and i(t)

Please check attached image for solution:

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How much more matter is in a golf ball than a ping pong?
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Explanation:

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3 years ago
How many kilocalories (Calories) does the snack bar contain?
laiz [17]

Answer:

See the explanation below.

Explanation:

Attached is a picture of a chocolate bar that can be easily found on the market. In this picture, we see the table of contents with the amount of energy that depends on the mass in grams of the chocolate bar.

We see that for the bar size of 100G, the energy value is 483 [kcal].

We can see that the energy depends on the size of the chocolate bar.

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3 years ago
Astronomers classify stars according to their (1 point) distance from Earth. color, size, and absolute brightness. age and paral
charle [14.2K]

Answer:

All of the above

Explanation:

Astronomers use all of those measures to classify stars. If you want to look more into classifying stars, check out the Hertzsprung-Russel Diagram. It covers how to identify red giants, main sequence, dwarf stars, ect. Distance from earth is typically measured in light years. The color of stars generally determines how hot they are. (Blue stars are the hottest) Also, the parallax method is used to measure stars that are closer to earth. This method relies heavily on geometry though.

Hope this helped!

8 0
3 years ago
What is the average velocity if the initial velocity of an object is 10 m/s & the final velocity is 28 m/s
Likurg_2 [28]

Answer:

v_{1}  = 19 m/s

Explanation:

v_{1}  = \frac{(v_{2}  + u)}{2}, where v_1<em> </em>= avg. velocity, v_2 = final velocity, and u = initial velocity.

6 0
3 years ago
Light rays in a material with index of refrection 1.29 1.29 can undergo total internal reflection when they strike the interface
deff fn [24]

Answer:

The second material's index of refraction is 1.17.

Explanation:

Given that,

Refractive index of the material, n = 1.29

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We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:

n_1\sin \theta_c=n_2\sin (90)\\\\n_2=n_1\sin \theta_c\\\\n_2=1.29\times \sin (65.9)\\\\n_2=1.17

So, the second material's index of refraction is 1.17.

7 0
3 years ago
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