Finish this equation useing the term "average speed" and "time interval ": total distance =
2 answers:
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Answer:
Explanation:
Here we will call:
1. : The energy when the first spring is compress
2. : The energy after the mass is liberated by the spring
3. : The energy before the second string catch the mass
4. : The energy when the second sping compressed
so, the law of the conservations of energy says that:
1.
2.
3.
where is the work of the friction.
1. equation 1 is equal to:
where K is the constant of the spring, x is the distance compressed, M is the mass and the velocity, so:
Solving for velocity, we get:
= 65.319 m/s
2. Now, equation 2 is equal to:
where M is the mass, the velocity in the situation 2,
is the velocity in the situation 3,
is the coefficient of the friction, N the normal force and d the distance, so:
Volving for , we get:
3. Finally, equation 3 is equal to:
where is the constant of the second spring and
is the compress of the second spring, so:
solving for , we get:
Answer:
a=1.25m/s²
Explanation:
GIVEN DATA
vi=10m/s
vf=15m/s
S=5m
TO FIND
a=?
SOLUTION
by using third equation of motion
2as=(vf)²-(vi)²
2a(5m)=(15m/s)²-(10m/s)²
10m×a=225m²/s²-100m²/s²
10m×a=125m²/s²
a=
a=12.5m/s²