Ask question

Ask question

All categories

3 years ago

12

Suzy has 7 separate rings as shown in the figure on the left. She wants to make one open chain as shown in the figure on the rig

ht. What is the least number of rings Suzy needs to cut?

1 answer:

Savatey [412]3 years ago

3 0

Answer:

every other one

Step-by-step explanation:

to put it specifically rings, 2, 4 and 6

You might be interested in

Kiera has $20 in a savings account. The interest rate is 5%

Anuta_ua [19.1K]

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

I = 20 × 0.05 × 2 = 2

I = $ 2.00

The simple interest accumulated

on a principal of $ 20.00

at a rate of 5% per year

for 2 years is $ 2.00.

8 0

3 years ago

Write the equation of a line that is perpendicular to y=3/2x+2 that goes through (6,-3)

scoray [572]

Answer:

$y + 3 = -\frac{2}{3}(x-6)$

Step-by-step explanation:

Perpendicular lines are lines which intersect at 90 degrees which have negative reciprocal slopes. The slope of the line y = 3/2x + 2 is 3/2. The slope of the line perpendicular to it will be -2/3. Substitute m = -2/3 and (6,-3) into the point slope form of a line.

$y - y_1 = m(x-x_1)\\y - -3 = -\frac{2}{3}(x-6)\\y + 3 = -\frac{2}{3}(x-6)$

4 0

4 years ago

how to transform the quantity of the fifth root of x to the seventh power, to the third power into an expression with a rational

Maurinko [17]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
\sqrt[5]{(x^7)^3}\implies \sqrt[5]{x^{7\cdot 3}}\implies \sqrt[5]{x^{21}}\implies x^{\cfrac{}{}\frac{21}{5}}$

8 0

3 years ago

Read 2 more answers

The probability that an event will not happen is Upper P (Upper E prime) = 0.94. Find the probability that the event will happen

xxMikexx [17]

Answer: P(Upper E' prime) = 0.06

Step-by-step explanation:

Not happen:P(Upper E prime) = 0.94

Happen: P(Upper E' prime) = ?

P(Upper E' prime) + P(Upper E' prime) = 1

Therefore

P(Upper E' prime) + 0.94= 1

P(Upper E' prime) =1- 0.94

P(Upper E' prime) = 0.06

5 0

3 years ago

Please help me to answer this question.

12345 [234]

Answer:

456,976,000

Step-by-step explanation:

The total number of possibilities is the product of the number of possibilities in each of the character positions:

10 · 10 · 10 · 26 · 26 · 26 · 26

= 10^3 · 26^4 = 456,976,000

5 0

3 years ago