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coldgirl [10]
3 years ago
11

Two boys are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upwar

d velocity of 36 ft/s. If acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?
Mathematics
2 answers:
omeli [17]3 years ago
6 0

Answer:

The ball is about 44 ft\\ above the ground

Step-by-step explanation:

As per newton's second law of motion

S = ut + \frac{1}{2} at^2\\

Substituting the given values in above equation, we get -

S = (36)(2) + \frac{1}{2} (-16)(2^2)\\= 40 ft\\

The total height including the height of ball from where it is throws

40 ft  + 4 ft\\= 44 ft\\

Deffense [45]3 years ago
3 0
The answer is a 12ft

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Let the base of the ladder be x ft and the extension be y ft.

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5 0
3 years ago
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