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NeTakaya
3 years ago
10

Simplify the radical expression. Leave it in radical form. SHOW YOUR WORK √75 + √3 √75 + √3

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
15+6<span>√3 is the correct answer.

Work:  
</span><span>√75 + √3 √75 + √3
5</span>√3+√3+√3*5√3
6√3+3*5
15+6√3
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Answer this math question pls I'm in a rush
777dan777 [17]

Answer:

61/18

Step-by-step explanation:

Make the mixed fraction an improper fraction first. So instead of 1 1/3, it'll be 4/3.

Now in a rectangular prism, there's two of each congruent sides (three pairs in total).

You'll need to multiply (4/3)(3/4) by 2 because there's two of them.

This gives you (1)(2) which equals 2.

Next, take another set --> (4/3)(1/3)(2) again because there's two of them.

This gives you (4/9)(2) which equals 8/9.

Last, take the last set --> (3/4)(1/3)(2)

This gives you (1/4)(2) which equals 1/2.

Now that you have all the areas of the rectangles, add them all together.

2+8/9+1/2 which equals 61/18 inches squared.

6 0
3 years ago
Determine the equation of the line that passes through the point (7, -23)and is perpendicular to the line y=1/3x-6Enter your ans
marishachu [46]

We have a line y = 1/3x -6

We want a line that is perpendicular to this line

Perpendicular lines have slopes that multiply to -1

1/3 * m = -1

3 * 1/3 *m = -1 * 3

m = -3

The slope of the perpendicular line is -3

y = mx+b where m is the slope and b is the y intercept

y = -3x+b

We have a point on the line ( 7 ,-23)

Substitute this point into the equation

-23 = -3(7)+b

-23 = -21+b

Add 21 to each side

-23+21 = -21+21+b

-2 = b

y = -3x-2

In slope intercept form, the line perpendicular passing through (7,-23) is

y = -3x-2

3 0
1 year ago
Can anyone please help??
Igoryamba
There are infinite numbers

7 0
3 years ago
Which statement about these equations is true?
Juliette [100K]

Answer:

Step-by-step explanation:

A:y=3x+4

7 0
3 years ago
Read 2 more answers
What is 8 2/5% of 75? Write your answer as a decimal
likoan [24]

Answer: 0.875

Step-by-step explanation:

The answer that has already been given is perfect in and by itself. I just want to give you some methods for doing these type of questions so that you won’t stagger when you see these type of questions in exams (like the SAT).

Whenever you see such questions, remember the following things. These are conversions of English words to Mathematical tools.

What

=

Any variable like

x

Percent / Percentage / %

=

Divide by 100

of

=

Multiply

is

=

Put an equal to (

=

) sign

I’ll give you an example through a question.

What percent of 200 is 5?

Ans: Replace English words by mathematical tools according to the rules I told you.

x

( What) /100 ( percent)

×

( of) 200

=

( is) 5

In a refined form,

x

100

×

200

=

5

Calculate x. On calculating, x comes out to be

2.5

So, 2.5 percent of 200 is 5.

Now your question is actually very simple if you follow my rules.

You want 87.5%. By the rules, % means divided by 100. So

87.5

%

=

87.5

100

and now using the same strategy, Ans:

875

1000

Disregard the next section if you know how to convert a decimal to a fraction

Section Starts

First, I’ll write the decimal form. Whenever you divide by a number that is in form of 1 followed by

n

number of zeroes. (here 1 is followed by 2 zeroes), you should shift the decimal point to the left side by n places.

In this case, shift decimal point in 87.5 to the left by 2 places. So this becomes 0.875.

This is the answer in decimal point.

Now simultaneously, I’ll teach you how to convert a decimal into a fraction.

Here, you see 2 types of “numbers”. One to the left side of the decimal point and one to the right side of the decimal point.

Here, left side of decimal point is 0 and right side of decimal point is 875.

Count the number of digits in the number to the right side of the decimal point (Here, the number of digits is 3)

Remove the decimal point and divide the number by a number formed by 1 followed by the “digits” we obtained (i.e. 3).

So, 875/1000. Simplify this, and you get your answer.

5 0
2 years ago
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