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dedylja [7]
4 years ago
11

A coordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1).

Mathematics
2 answers:
irina [24]4 years ago
8 0

Answer:

Standard form: 4x-5y=9

x-intercept: 9/4

y-intercept: -9/5

Step-by-step explanation:

Edgenuity

Ksju [112]4 years ago
7 0

Answer:

4x - 5y - 9 = 0

\frac{9}{4}

\frac{-9}{5}

Step-by-step explanation:

The equation of a straight line passing through the points (-4,-5) and (1,-1) is given by \frac{y - (-5)}{-5-(-1)} =\frac{x-(-4)}{-4-1}

⇒ \frac{y+5}{-4} =\frac{x+4}{-5}

⇒ 5y + 25 = 4x + 16

⇒ 4x - 5y - 9 = 0 ....(1) (Answer)

Now, this above equation can be represented as

\frac{x}{\frac{9}{4} } + \frac{y}{\frac{-9}{5} } =1

Therefore, the x-intercept is \frac{9}{4} (Answer)

And the y-intercept is \frac{-9}{5}. (Answer)

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Step-by-step explanation:

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Consider the initial value problem y′′+36y=2cos(6t),y(0)=0,y′(0)=0. y″+36y=2cos⁡(6t),y(0)=0,y′(0)=0. Take the Laplace transform
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