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2 years ago

Can someone help me solve this?

Mathematics

1 answer:

Luda [366]2 years ago

8 0

Answer:

$\dfrac{7\pi}{18}$

Step by step explanation:

$70^{\circ}=\dfrac{70\pi}{180}~~\text{radians}=\dfrac{7\pi}{18}~~\text{radians}$

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Solve to find side C please

Alex73 [517]

Answer:

c= 18.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos theta = a/c

cos 57 = 10/c

Multiply each side by c

c cos 57 =10

Divide each side by cos 57

c = 10/cos 57

c=18.36078459

Rounding to the nearest tenth

c= 18.4

6 0

3 years ago

NEED HELP ASAP I WILL RATE 5 STARS

masha68 [24]

Answer:

Step-by-step explanation:

If you plug in 5 1/3 to the equation, the result is 6, meaning that the point lies on the line.

5 0

3 years ago

Mike can make 7 holiday cards with the cardstock he already has on hand. He is also buying more paper, and he can make 12 additi

ipn [44]

Answer:y = 12x + 7

Step-by-step explanation:

8 0

1 year ago

13.......................

Alla [95]

Answer:

The answer is (d) ⇒ $pq^{2}r\sqrt[3]{pr^{2}}$

Step-by-step explanation:

* To simplify the cube roots:

If its number then the number must be written in the form x³

then we divide the power by 3 to cancel the radical

If its variable we divide its power by 3 to cancel the radical

∵ $\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}$

∴ $p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}$

∵ $p^{\frac{1}{3}}=\sqrt[3]{p}$

∵ $r^{\frac{2}{3}}=\sqrt[3]{r^{2}}$

∴ $p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})$

∴ $prq^{2}\sqrt[3]{pr^{2}}}$

∴ The answer is (d)

5 0

3 years ago

15% of blank is 42 help me plz

marin [14]

42/.15=280
So 280
You divide 42 by 15%
15 percent is .15

5 0

3 years ago