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oksano4ka [1.4K]
3 years ago
15

Two-fifths of the girls signed up to play softball. An equal number of girls signed up to play pitcher, infield, and outfield. W

hat fraction of girls in the school signed up to play outfield?
Any help appreciated, thank you!
Mathematics
1 answer:
Gwar [14]3 years ago
3 0
If there were 30 Girls, 4 Girls played for each part.
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Y = -8<br><br> Y = -2x - 12 <br><br> Solve this equation by substitution
aliina [53]

Answer:

x = - 2

Step-by-step explanation:

- 8 = - 2x - 12

- 8 + 12 = - 2x - 12 + 12

- 2x = 4

- 2x ÷ - 2 = 4 ÷ - 2

x = - 2

5 0
2 years ago
Simplify the radical expression by rationalizing the denominator.9 square root of 25 divided by the square root of 50
Crank
(9√25) /√50 = 9*5/√50 now simplify the denominator. √50=√25*√2=5√2
so (9*5)/(5√2) simplifies to 9/√2. To rationalize the denominator multiply both the numerator and the denominator by √2.
9√2/(√2*√2) = 9√2/2

4 0
3 years ago
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the graph of the function f(x)= -(x-6)(x+2) is shown below which statement about the function is true
ololo11 [35]
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5 0
3 years ago
a) Suppose that a large mixing tank initially holds 300 gallons of water in which 50 pounds ofsalt have been dissolved. Pure wat
Kay [80]

Answer:

x  =  50*e∧ -t/100

Step-by-step explanation:

We assume:

1.-That the volume of mixing is always constant 300 gallons

2.-The mixing is instantaneous

Δ(x)t   =  Amount in  - Amount out

Amount  =  rate * concentration*Δt

Amount in  =  3 gallons/ min * 0  =  0

Amount out  = 3 gallons/min *  x/ 300*Δt

Then

Δ(x)t/Δt  =  - 3*x/300    Δt⇒0   lim Δ(x)t/Δt  =  dx/dt

dx/dt  =  - x/100

dx/ x  =  - dt/100

A linear first degree differential equation

∫ dx/x   =  ∫ - dt/100

Ln x  =  - t/100  +  C

initial conditions to determine C

t= 0     x =  50 pounds

Ln (50) = 0/100 * C

C =  ln (50)

Then final solution is:

Ln x  =  - t/100  + Ln(50)   or

e∧ Lnx   =  e ∧ ( -t/100 + Ln(50))

x  =  e∧ ( -t/100) * e∧Ln(50)

x  = e∧ ( -t/100) * 50

x  =  50*e∧ -t/100

4 0
2 years ago
Use the graph of f(x) = log x to obtain the graph of g(x) = log x + 5.
galina1969 [7]

The graph of g(x) = f(x) + 5 will have the graph of f(x) moved 5 units upward. The best choice is the last one.

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Adding 5 to each y-value (the output of f(x)) moves it upward by 5 units.

8 0
3 years ago
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