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3 years ago

15

Your class built a tepee to use in the school play. The tepee has a diameter of 16 feet and a height of 13.5 feet. What is the v

olume? Use 3.14 for pi. Round your answer to the nearest whole number.

1 answer:

professor190 [17]3 years ago

8 0

Answer:

904.78

Step-by-step:

V=πr2h

3=π·82·13.5

3≈904.77868

Hope this helps

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Kia paid $10 for two charms. The price of each charm was a multiple of $2. What are the possible prices for the charms?

Fiesta28 [93]

Kia paid 20$ for each of her charms

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3 years ago

Read 2 more answers

Given the figure above, determine

tensa zangetsu [6.8K]

Answer: Angle 2 = 47 degree

Explanation:

Proof that triangle ACB ~ triangle CBD

Angle ABC = Angle CBD (same angle)

If one pair of the angle is the same then the other pair should also be equal because both the triangle are Isosceles.

=> angle ACD = Angle CDB

Therefore, triangle ACB ~ triangle CBD (AA)

=> angle C = Angle A

But angle A = 47 degree

Therefore, Angle C = Angle 2 = 47 degree

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2 years ago

A) Let f(x) = 4x + 2 and g(x) = 2x^2-4. Find the formula for the composition function gof

ollegr [7]

Answer:

g o f = $g(f(x)) = 32x^2 + 32x + 4$

Step-by-step explanation:

Given

$f(x) = 4x +2$

$g(x) =2x^2 - 4$

Required:

Find g o f

This is calculated as:

$gof = g(f(x))$

$g(x) =2x^2 - 4$

So:

$g(f(x)) = 2(4x+2)^2 - 4$

$g(f(x)) = 2(4x+2)(4x+2) - 4$

$g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4$

$g(f(x)) = 32x^2 + 32x + 8 - 4$

$g(f(x)) = 32x^2 + 32x + 4$

5 0

3 years ago

the sum of three numbers is 131. the third number is 4 times the first. the second number is 5 more than the first. what are the

Sphinxa [80]

Step-by-step explanation:

let the numbers are:

a, b, and c

the equation would be:

a+b+c = 131

c = 4a

b = a+5

=>

a + a+5 +4a = 131

6a +5 = 131

6a = 131-5

6a = 126

a= 126/6

a = 21

b = a+5 = 21+5

b = 26

c = 4a = 4(21)

c = 84

4 0

2 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0

3 years ago