3 years ago

What needs to be done to this circuit so that the light bulb lights up?

Physics

2 answers:

kramer3 years ago

6 0

A) close the switch
I took the test

Pachacha [2.7K]3 years ago

5 0

The answer is the first one a

You might be interested in

Neglecting air resistance which of the following statements is not true regarding the motion of a ball thrown vertically with an

inysia [295]

Answer:

c or b

Explanation:

6 0

3 years ago

Relative to the ground, what is the gravitational potential energy of 68 kg

Kisachek [45]

Answer:

Explanation:

p.E=mgh

P.E=68*10*443

p.E=301240j

8 0

2 years ago

You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s

Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

$W = \dfrac{1}{2}kx^2$

$5 = \dfrac{1}{2}kx^2$ ............(1)

Work done in compression of spring at higher setting

$W' = \dfrac{1}{2}kx'^2$

$W'= \dfrac{1}{2}k(2x)^2$

$W'= 4\times \dfrac{1}{2}kx^2$

$W'= 4\times W$

from equation (1)

$W'= 4\times 5$

W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0

3 years ago

A 1/10th scale model of an airplane is tested in a wind tunnel. The reynolds number of the model is the same as that of the full

trasher [3.6K]

Answer:

of the velocity of a full size plane in the air

7 0

4 years ago

Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud

Levart [38]

Explanation:

Given that,

Charge 1, $q_1=-5.45\times 10^{-6}\ C$

Charge 2, $q_2=4.39\times 10^{-6}\ C$

Distance between charges, r = 0.0209 m

1. The electric force is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}$

F = -492.95 N

2. Distance between two identical charges, $r=0.0209\ m$

Electric force is given by :

$F=\dfrac{kq_3^2}{r^2}$

$q_3=\sqrt{\dfrac{Fr^2}{k}}$

$q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}$

$q_3=4.89\times 10^{-6}\ C$

Hence, this is the required solution.

3 0

3 years ago