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Charra [1.4K]
2 years ago
14

A rifle is aimed horizontally at a target 50.0 m away. The bullet hits the target 2.90 cm below the aim point. . . Whats the bul

let's flight time?. Whats the bullet's speed as it left the barrel?
Physics
1 answer:
Marina CMI [18]2 years ago
5 0
The problem ask to calculate the bullet's flight time and the bullet's speed as it left the barrel. So base on the problem, the answer would be that the flight time is 0.076 seconds and the speed of the bullet is 657.9 m/s. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications. 
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For a rigid body in rotational motion, what can be stated about the angular velocity of all of the particles? The linear velocit
Andru [333]

Answer:

Explanation:

In case of rotational motion, every particle is rotated with a same angular velocity .

The relation between linear velocity and angular velocity is

V = r w

Where v is linear velocity, r is the radius of circular path and w be the angular velocity.

Here w is same for all the particles but every particle has different radius of circular path I which they are rotating, so linear velocity is differnet for all.

7 0
2 years ago
A tennis ball and a solid steel ball of the same diameter are dropped at the same time. Ignoring the air resistance effects, whi
Paha777 [63]
Yes I have the answer
6 0
3 years ago
220V and 5A is supplied to the primary coil. The turns ratio is 500. What is the power on the secondary coil?
alisha [4.7K]

Answer: 1100 W

Explanation:

Input power  = 220(5) = 1100 W

The transformer will step up/down voltage, but will also step down/up current.

Neglecting hysteresis and other minor losses, the power will remain the same.

4 0
2 years ago
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
Andreyy89

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

P=V*I

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

P=110*8.47\\P=931.7[W]

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min]

3 0
3 years ago
The speed of an electromagnetic wave is a constant, 3.0 × 108 m/s. The wavelength of a wave is 0.3 meters. What is the frequency
mojhsa [17]
It would be 1.0 x 10^6 Hz
6 0
3 years ago
Read 2 more answers
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