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MissTica
3 years ago
7

A block moves along a table at a constant velocity and then rolls off the edge of the table. The forces that should be included

in a free body diagram for the ball as it falls to the ground are:
normal force from table
friction force from table
gravity
force of fall
Physics
1 answer:
Alla [95]3 years ago
3 0

Answer:

Gravity

Explanation:

When the ball is falling to the ground, there is only one force- gravity. In some cases, there may be air resistance, but that seems to be neglected here.

Normal force:

Cannot be included. Normal force is only applicable when object is on a surface, and it acts perpendicular to the surface. Since the ball is falling, there is no surface, and therefore no normal force. This question gives you unnecessary information, designed to trick you. Please remember when normal force is applicable.

Friction force:

Also only applicable when object is moving, and is on the table. Friction only applies when there is an applied force. There is no applied force when the ball is falling, so therefore no friction force.

Force of fall:

First of all, what is this? There is nothing called force of fall.

Gravity:

This is the only one that applies. Just draw a vector arrow from the bottom of the ball and label it mg (acceleration due to gravity).

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4 0
4 years ago
The speed of the bus is 40km/hr. what does it mean?​
kiruha [24]

Answer:

The speed of the bus is 40 km/hr so this means the bus is travelling at a speed of 40 km per hour.

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4 years ago
A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). What is the force of gravity between them(G=6.67*10^-11N•m^2/kg^2)
gregori [183]

Answer:

F = 2.668*10_-6[N]

Explanation:

We can calculate this force using the law of universal gravitation raised by Isaac Newton

m_{t}=20000[kg]\\m_{c}= 200[kg]\\r = 10[m]\\G = 6.67*10^{-11}[\frac{N*m^{2} }{kg} ] \\

And the force is given by the following expression:

F=G*\frac{m_{t}*m_{c}}{r^{2} } \\F=6.67*10^{-11} *\frac{20000*200}{10^{2} }\\F=2.668*10^{-6} [N]

5 0
3 years ago
In an unweathered sample of igneous rock, the ratio of an unstable isotope to its stable daughter isotope is 1:15. If no daughte
svlad2 [7]

Answer:

200 million years

Explanation:

The equation that describes the decay of a radioactive isotope is

N(t)=N_0 (\frac{1}{2})^{\frac{t}{t_{1/2}}}

where

N(t) is the amount of radioactive isotope left at time t

N_0 is the initial amount of isotope

t_{1/2} is the half-life of the sample

In this problem, the ratio between unstable isotope and daughter isotope is 1:15; this means that

\frac{N(t)}{N_0}=\frac{1}{16}

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Also we know that the half-life is

t_{1/2}=50\cdot 10^6 y

So we can re-arrange the equation to find t, the age of the rock:

t=t_{1/2} log_{0.5}(\frac{N}{N_0})=(50\cdot 10^6)log_{0.5}(\frac{1}{16})=200\cdot 10^6 y

So, 200 million years.

6 0
4 years ago
find the distance traveled in km when the average speed is 60 km per hour and the time taken is 3 and 1/2 hours​
Anna35 [415]

Answer:

210 km

Explanation:

60 x 3  1/2 = 210

3 0
3 years ago
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