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3 years ago

Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite

Physics

2 answers:

mr Goodwill [35]3 years ago

8 0

<h2>Answer </h2>

1) iron

2) aluminium

3) silver

4) copper

Sedaia [141]3 years ago

6 0

<h2>Answer </h2>

<h3>2) Aluminium </h3>

<h3>3) sliver </h3>

<h3>4) copper </h3>

I hope it's helpful for you ☺️

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An object is moving in the absence of a net force. Which of the following best describes the object's motion? -please help?

Gelneren [198K]

You can solve this by using Newton's First Law or Newton's Second Law.

1) Newton's First Law or Inertia Law states that in the abscense of a net force acting over an object, this will not chage its state of movement, i.e it will remain at rest (if it is no moving) or with uniform movement (if the object is moving).

2) Newton's Second Law: Net force = mass * acceleration => acceleration = net force / mass = 0 / mass = 0.

Zero accelerations means rest or uniform movement.

First Law is implicit in Second Law.

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3 years ago

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Anastaziya [24]

Answer:

PE is related to the ability to do work, If an item is sitting on a shelf

it has potential energy relative to its position on the floor, However, if the object were to fall it would hit the floor with a KE equal to the PE that it had sitting on the shelf.

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2 years ago

A system of two paint buckets connected by a lightweight rope is released from rest with the 12.0-kg bucket 2.00 m above the flo

NISA [10]

Explanation:

The given data is as follows.

Mass of small bucket (m) = 4 kg

Mass of big bucket (M) = 12 kg

Initial velocity ( $v_{o}$ ) = 0 m/s

Final velocity ( $v_{f}$ ) = ?

Height $H_{o} = h_{f}$ = 2 m

and, $H_{f} = h_{o}$ = 0 m

Now, according to the law of conservation of energy

starting conditions = final conditions

$\frac{1}{2}MV^{2}_{o} + Mgh_{o} + \frac{1}{2}mv^{2}_{o} + mgh_{o} = \frac{1}{2}MV^{2}_{f} + Mgh_{f} + \frac{1}{2}mv^{2}_{f} + mgh_{f}$

$\frac{1}{2}(12)(0)^{2} + (12)(9.81)(2) + \frac{1}{2}(4)(0)^{2} + (4)(9.81)(0) = \frac{1}{2}(12)V^{2}_{f} + (12)(9.81)(0) + \frac{1}{2}(4)V^{2}_{f} + (4)(9.81)(2)$

235.44 = $8V^{2}_{f}$ + 78.48

$V_{f}$ = 4.43 m/s

Thus, we can conclude that the speed with which this bucket strikes the floor is 4.43 m/s.

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3 years ago

The magnitude of vector A is 10. Which of the following could be the components of A?

kotykmax [81]

Answer: B. Ax = 6, Ay=8

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3 years ago

PIUDICITIS CONSECulvely and Circle your aliswers. Lilyo

mihalych1998 [28]

Answer:

The angular acceleration of CD player is $13.93\ rad/s^2$ .

Explanation:

Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.

It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :

$a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2$

So, the angular acceleration of CD player is $13.93\ rad/s^2$ .

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3 years ago

Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite​

Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite