A body of mass 36 g moves with SHM of amplitude A = 13 cm and period T = 12 s. At
1 answer:
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Answer:
W = 750 [J]
Explanation:
The question should be related to work, work in physics is defined as the product of force by distance. In this way, we can use the following equation.
where:
F = force = 30 [N]
d = distance = 25 [m]
W = work [J]
Now replacing:
Answer:
1.77 m/s^2
Explanation:
There are two forces acting on the car along the direction parallel to the incline:
- The driving force of 10,000 N, which pushes forward
- The component of the weigth of the car parallel to the incline, which pulls backward
The component of the weight of the car parallel to the incline is:
So now we can apply Newton's second law to find the acceleration of the car:
Answer:
It would take 16.7 s for the work to be done by the engine.
Explanation:
From the question, given: Power = 390.3 kW
Work to be done = 6.5 x J
But, power and work done with respect to time, has a relationship of:
Power =
So that,
time =
Thus,
time =
= 16.6539
time = 16.7 s
Time required is 16.7 seconds.
Thus, it would take 16.7 s for the work to be done by the engine.