Answer:
Inelastic
Explanation:
When the price of hamburgers increased from $1.50 to $2.75, the quantity demanded decreased from 375 units sold to 250 units sold. Using the midpoint method, hamburgers are said to be inelastic
1. Change in price = 2.75-1.5 / (1.5+2.75)/2 = 1.25/2.125 = 0.59
2. Change in quantity demanded = 375-250 / (375+250)/2 = 125/ 312.5 = 0.4
3. Price Elasticity = 0.4/0.59 = 0.68
4. When the value of elasticity is less than 1, it suggests that the demand is insensitive to price and is inelastic
Answer:
The correct answer is C
Explanation:
HRM system is the system which is designed in order to automate the business process of human resource, compliance, transactions and payroll. This system allows the business to focus on the people through streamlining all the software workforce into the business intelligence solution.
Recruitment and selection is the procedure of identifying the requirement of job and defining the need of the position, advertising the position and selecting the appropriate person for the position.
Therefore, the recruitment and selection is the component of HRM system which uses the hiring procedure that comprise of testing and interviewing the professionals.
Answer:
religion
race
Explanation:
Diversity in the workplace is a deliberate attempt to incorporate a wide range of different workers. It is an appreciation that each person or group of people is unique and has diverse characteristics. Workplace diversity results in the organization being accommodative to diverse cultures and different identities.
Workplace diversity embraces race, gender, age, sexual orientation, ethnic groups, religion, sexual orientation, and physical conditions. It also includes other unique differences between people.
The average score of the student in the class at a 99% confidence lies between 1.252 and 3.028
Explanation:
Given values are
n = 14 = 2.14 σ = 1.29 z value for 99% confidence = 2.576
The mean is known one
= (z σ/√14)
= (2.576 ×1.29÷√14)

= 2.576 × 0.345
= 0.888
= mean- 0.888 = 2.14 - 0.888 = 1.252
= mean+0.888 = 2.14 + 0.888 = 3.028
The average score of the students in the class at a 99% confidence lies between 1.252 and 3.028