Answer:
A solution that results in a false statement when substituted back into the original equation.
Step-by-step explanation:
An extraneous solution is one that arises in a solution of equations, but which on closer inspection is not a solution to the original equation. Therefore, they imply an error in the development of the solution of the equation, so they cannot be taken as a valid solution since, when replacing the result with the missing variable, the equation does not obtain the desired result.
Answer:
a) 2-5 = -3
b) 3(4) + 2(4) = 20
c) (3(5)+2)(5-4) = 17
Step-by-step explanation:
Substitute the variables for their values and then solve from there. Hopefully this helps, I don't know if I answered your question fully.
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
Answer:
x = (-150)/49
Step-by-step explanation:
Solve for x:
49 x + 150 = 0
Hint: | Isolate terms with x to the left hand side.
Subtract 150 from both sides:
49 x + (150 - 150) = -150
Hint: | Look for the difference of two identical terms.
150 - 150 = 0:
49 x = -150
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 49 x = -150 by 49:
(49 x)/49 = (-150)/49
Hint: | Any nonzero number divided by itself is one.
49/49 = 1:
Answer: x = (-150)/49
