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NeX [460]
3 years ago
5

PLEASE HELP AS SOON AS POSSIBLE!!!!!!!!!!!!!!!!!! |r+3| ≥7 solve the inequality (please show work and steps )

Mathematics
2 answers:
alexdok [17]3 years ago
6 0
|r+3| = (r+3) when r ≥ -3 so for r ≥ -3
                        r + 3 ≥ 7
                               r ≥ 4
|r+3| = -(r+3) when r < -3 so for r < -3
                     -(r + 3) ≥ 7
                         r + 3 ≤ -7
                               r ≤ -10
The answer to this question is r ≤ -10, r ≥ 4
TEA [102]3 years ago
4 0
So the solution would be:
|r+3| = (r+3)
r + 3 ≥ 7
  r ≥ 4
|r+3| = -(r+3)
  -(r + 3) ≥ 7
   r + 3 ≤ -7
r ≤ -10
So the answer is r ≤ -10, r ≥ 4
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What is the solution set for the following system of equations 5x-3y-10=0 x+y-7=0
garik1379 [7]

(x, y) = ( \frac{31}{8}, \frac{25}{8})

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6 0
3 years ago
Another quick geometry question! Thanks!
miss Akunina [59]
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so x=21
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2 years ago
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