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wlad13 [49]
3 years ago
13

HClO4 acid solution has a concentration of 5 Molarity. Calculate the concentration of this solution in

Chemistry
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

1. Percentage by weight = 0.5023 = 50.23 %

2. molar fraction =0.153

Explanation:

We know that

Molar mass of HClO4 = 100.46 g/mol

So the mass of 5 Moles= 5 x 100.46

       Mass (m)= 5 x 100.46 = 502.3 g

Lets assume that aqueous solution of HClO4  and the density of solution is equal to density of water.

Given that concentration HClO4 is 5 M it means that it have 5 moles of HClO4 in 1000 ml.

We know that

Mass = density x volume

Mass of 1000 ml  solution = 1 x 1000 =1000     ( density = 1 gm/ml)

            m'=1000 g

1.

Percentage by weight = 502.3 /1000

Percentage by weight = 0.5023 = 50.23 %

2.

We know that

molar mass of water = 18 g/mol

mass of water in 1000 ml = 1000 - 502.3 g=497.9 g

So moles of water = 497.7 /18 mole

moles of water = 27.65 moles

So molar fraction = 5/(5+27.65)

molar fraction =0.153

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Answer:

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+(aq)

Explanation:

Step 1: The unbalanced equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

Step 2: Balancing the equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the right side we have 2x NO3, on the left side we have 1x NO3.

To balance the amount of NO3 on both sides, we have to multiply AgNO3 (on the left side) by 2.

Pb(s) + 2AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the left side we have 2x Ag, on the right side we have 1x Ag.

To balance the amount of Ag on both sides, we have to multiply Ag (on the right side) by 2. Now the equation is balanced.

Pb(s) + 2AgNO3(aq) → 2Ag(s) + Pb(NO3)2(aq)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+

8 0
4 years ago
Ethylene glycol flows at 0.01 kg/s through a 3-mm diameter, thin-walled tube. The tube is coiled and submerged in well-stirred w
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Answer:

heat rate= 1281W

length = 15.8m

Explanation:

we have this data to answer this question with

Tmi = 85 degrees

Tmo = 35 degrees

Ts = 25 dgrees

flow rate = 25 degrees

using engine oil property from table a-5

Tm = Tmo - TMi/2 = 333k

u =0.522x10⁻²

k = 0.26

pr = 51.3

cp = 2562 J/kg.k

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we find the change in Tim

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= 0.04/0.00004921

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we find approximate correlation

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NuD = 3.66

3.66 = 0.003D/0.26

cross multiply

0.003D = 3.66x0.26

D = 3.66x0.26/0.003

= 317.2

As = 1281/317x27.9

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3 years ago
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The KM value for an enzyme depends on the particular substrate and on environmental conditions such as pH, temperature, and ionic strength.

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