Given:
Molar mass of CO2 = 44.01g/mol
3.21x10^25 molecules of CO2
Required:
Mass of CO2
Solution:
Avogadro’s number states that
for every mole of atom, there are 6.023x10^23 units of atom. The units may be
formula units, atoms. In here, you need to divide 3.21x10^25 molecules of CO2
to 6.023x10^23 molecules per mole.
3.21x10^25 molecules of CO2 / 6.023x10^23
molecules per mole = 53.30 moles CO2
53.30 moles CO2 (44.01g/mol CO2)
= 2346 g of CO2
I think this answer is D or C
Answer:
The molar mass of Mg(NO₃)₂, 148.3 g/mol.
Explanation:
Step 1: Given data
- Mass of Mg(NO₃)₂ (solute): 42.0 g
- Volume of solution: 259 mL = 0.259 L
Step 2: Calculate the moles of solute
To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.
42.0 g × 1 mol/148.3 g = 0.283 mol
Step 3: Calculate the molarity of the solution
M = moles of solute / liters of solution
M = 0.283 mol / 0.259 L
M = 1.09 M
B it is an aldose to ketose isomerization
