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alexgriva [62]
3 years ago
11

PLS HELPPPP NOWWWW!!!!

Chemistry
1 answer:
dedylja [7]3 years ago
8 0
When in doubt pick C I don’t really know the answer but I just pick C
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I need help with chemistry :(
Yanka [14]

Answer:

How may we help kind sir

Explanation:

and if this was for points thanks

4 0
3 years ago
Read 2 more answers
At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?
ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}

Pressure=\frac{densityXRT}{molarmass}

molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50

Thus molar mass of gas is 37.50g/mol

6 0
3 years ago
Write the steps for calculating molar mass.
Marizza181 [45]

Answer:

Explanation:

1) Find number of each of the type of atom that is present in the compound, using the chemical formula .

2) Then multiply number of atoms of each element that is present in the compound with the atomic weight of each of the element

3) Add everything together and add the units (grams/mole ) after the number

Let finds that of water

Chemical formula of water is (H20 )

hydogens atoms= 2

oxygen atom= 1

Atomic weight for Hydrogen= 1

Atomic weight for Oxygen= 16

Total number of atoms of Hydrogen from the formula (H2O)= 2

Total number of atoms of Oxygen from the formula (H2O)= 1

the molar mass=

Hydrogen: ( 2 x 1)= 2

Oxygen: ( 1 x 16)= 16

Add together= (16+2)

= 18

Then add the unit, we have(18 g/mol.)

5 0
3 years ago
Please help..
Hoochie [10]

Answer:

1.

Explanation:

Let's start with the hydrogen. If we have 4 grams of hydrogen, it would be enough for 4 * 9 = 36 grams of water. Well, that can't be possible ...

4 votes

8 0
2 years ago
In laboratory experiment, a NOVDEC Student was
Ede4ka [16]

Answer:

i. Molar mass of glucose = 180 g/mol

ii. Amount of glucose = 0.5 mole

Explanation:

<em>The volume of the glucose solution to be prepared</em> = 500 cm^3

<em>Molarity of the glucose solution to be prepared</em> = 1 M

i. Molar mass of glucose (C_1_2H_6O_6) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

ii.<em> mole = molarity x volume</em>. Hence;

amount (in moles) of the glucose solution to be prepared

                 = 1 x 500/1000 = 0.5 mole

3 0
3 years ago
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