The eagle gained 882 J of gravitational potential energy.
Answer:
59.4 meters
Explanation:
The correct question statement is :
A floor polisher has a rotating disk that has a 15-cm radius. The disk rotates at a constant angular velocity of 1.4 rev/s and is covered with a soft material that does the polishing. An operator holds the polisher in one place for 4.5 s, in order to buff an especially scuff ed area of the floor. How far (in meters) does a spot on the outer edge of the disk move during this time?
Solution:
We know for a circle of radius r and θ angle by an arc of length S at the center,
S=rθ
This gives
θ=S/r
also we know angular velocity
ω=θ/t where t is time
or
θ=ωt
and we know
1 revolution =2π radians
From this we have
angular velocity ω = 1.4 revolutions per sec = 1.4×2π radians /sec = 1.4×3.14×2×= 8.8 radians / sec
Putting values of ω and time t in
θ=ωt
we have
θ= 8.8 rad / sec × 4.5 sec
θ= 396 radians
We are given radius r = 15 cm = 15 ×0.01 m=0.15 m (because 1 m= 100 cm and hence, 1 cm = 0.01 m)
put this value of θ and r in
S=rθ
we have
S= 396 radians ×0.15 m=59.4 m
First get a map and measure how far you are from your original destination since the destination is not well identified where it is in Michigan so just get an approximate distance and then do the calculations
<span>A very rare type of lightning that appears as a reddish-colored sphere is called </span>A + Ball Lightening
Answer:
9.5 seconds
Explanation:
You need to make the ending speed into meters per sec.
So it would be 120km/h = 33.33m/s
If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds
Also btw rounding it up is a good idea too so 10 seconds if you round