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4 years ago

During any process, the net electric charge of an isolated system does not change.

Physics

1 answer:

astraxan [27]4 years ago

5 0

Answer:

Due to the Electric Charge Conservation Law, the statement is true.

Explanation:

Conservation laws state that the physical properties or magnitudes of a given system have a constant value, that is, they cannot change.

Electric charge is a property that exists in some subatomic particles, manifested by attractions and repulsions that give rise to electromagnetic interactions.

The electric charge is governed by the principle of conservation of the charge. This law establishes that the total load in an isolated system is constant, that is, it is not possible to create or destroy isolated loads. That is, they can only be moved from one body to another or from one place to another inside the given body.

As mentioned, this law is only valid for closed systems in which no charged particles enter or leave outside. Then it is concluded that the algebraic sum of the charges of all particles remains constant.

Finally, due to the Electric Charge Conservation Law, the statement is true.

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Answer:

(A) it's acceleration is negative but but it's velocity is positive

Explanation:

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Now the acceleration is the rate of change of velocity

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So acceleration is negative here

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3 years ago

A charge of 8.0 pc is distributed uniformly on a spherical surface (radius = 2.0 cm), and a second charge of â3.0 pc is distribu

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According to Gauss' law, the electric field outside a spherical surface uniformly charged is equal to the electric field if the whole charge were concentrated at the center of the sphere.

Therefore, when you are outside two spheres, the electric field will be the overlapping of the two electric fields:
E(r > r₂ > r₁) = k · q₁/r² + k · q₂/r² = k · (q₁ + q₂) / r²
where:
k = 9×10⁹ N·m²/C²

We have to transform our data into the correct units of measurement:
q₁ = 8.0 pC = 8.0×10⁻¹² C
q₂ = 3.0 pC = 3.0×10⁻¹² C
r = 5.0 cm = 0.05 m

Now, we can apply the formula:
E(r) = k · (q₁ + q₂) / r²
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= 39.6 N/C

Hence, the magnitude of the electric field 5.0 cm from the center of the two surfaces is E = 39.6 N/C

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Answer:

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