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Black_prince [1.1K]
4 years ago
12

A flying squirrel is gliding (no wing flaps) to the ground at a constant velocity

Physics
1 answer:
Leno4ka [110]4 years ago
5 0

Answer:

See attached figure

Explanation:

The FBD (Free Body Diagram) of an object represents the forces acting on the object.

In this problem, the squirrel is moving at constant velocity. Constant velocity means that its acceleration, therefore the net force acting on the squirrel must be zero as well, according to Newton's second law:

F=ma=0

where F is the net force, m is the mass of the squirrel, a is its acceleration.

There are only two forces acting on the squirrel:

- The force of gravity, also called weight, acting downward, of magnitude (mg) (where m is the mass of the squirrel and g is the acceleration of gravity)

- The air resistance, R, upward

Since the net force is zero, the two forces are balanced, therefore they have same magnitude, and they are represented in the graph as two arrows of same length.

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A pitcher throws a baseball that reaches the catcher in 0.75 s. The ball curves because it is spinning at an average angular vel
7nadin3 [17]

The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

\omega = \frac{\theta}{t}

Here,

\theta = Angular displacement

t = time

The angular velocity is given as

\omega = 230rev/min

PART A) The angular velocity in SI Units will be,

\omega = 230rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega = \frac{23}{3}\pi rad/s \approx 24.08rad/s

PART B) From our first equation we can rearrange to find the angular displacement then

\theta = \omega t

Replacing,

\theta = (24.08)(0.75)

\theta = 18.06 rad

4 0
3 years ago
A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are
igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

T = I\alpha = 0.303*0.6454 = 0.196 Nm

So the force acting on the other end to generate this torque mush be:

F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N

4 0
4 years ago
Which of the following is a true statement about mass and weight? Mass is a measure of how much matter an object has, while weig
marusya05 [52]

Answer:

Mass will not change based on location, while weight will change based on gravitational pull.

Explanation:

The formula for weight is mass*gravitational pull, hence weight changes based on gravitational pull

3 0
4 years ago
Neglecting air​ resistance, the distance s left parenthesis t right parenthesis in feet traveled by a freely falling object is g
ivann1987 [24]

Explanation:

It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet

The distance traveled by a freely falling object is given by :

s(t)=16t^2

16t^2=862

t=\sqrt{53.875}

t = 7.34 seconds

So, the object will take 7.34 seconds to fall to the ground from the top of the​ building. Hence, this is the required solution.

7 0
3 years ago
Please help
inysia [295]

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

a =?

3N = 6kg x a

solve for a

3N / 6kg = a

3 0
3 years ago
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