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fiasKO [112]
3 years ago
10

What is the critical angle and how does it relate to total internal reflection?

Physics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

critical angle is the angle of incidence in optically denser medium, for which the angle of reflection in the less denser medium is 90 degree

Explanation:

total internal reflection occurs at one particular angle of incidence where the reflected ray lies on the boundary.

this angle is called the critical angle

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Groundwater is desirable for which of the following reasons?
Akimi4 [234]

the answer is B. surface water can seep downward to become groundwater

5 0
3 years ago
In the formula for magnetic deflection, FM is equal to qvB. Match each symbol in this formula with what it represents.
slava [35]

Answer:

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

Explanation:

We are given that magnetic  deflection

F_m=qvB

We have to match each symbol in formula with what it  represents.

In this formula

F_m=Deflection force

q=Charge of particle

v=Velocity of charge

B=Perpendicular magnetic field strength

Therefore,

1.F_m-Deflection force

2.q-Charge

3.v-Velocity of the charge

4.B-Perpendicular magnetic field strength

8 0
3 years ago
Read 2 more answers
A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s
sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

Considering vertical motion of projectile:

Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

             v² = 98.96² + 2 x -9.81 x -208

             v = 117.79 m/s

Final velocity,

            v=\sqrt{138.23^2+117.79^2}=181.61m/s

            \theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0
4 years ago
Absolute zero (K=0 or -273.15°C) is what temperature on the Farenheit scale? a) 459.4°F b) -301.43 °F c) 233.05°F d) -40.15°F e
ANEK [815]

Answer:

e) None of these is true

Explanation:

Given that

Temperature = 0 K

We know that relationship between kelvin and Farenheit scale

\dfrac{K-273}{100}=\dfrac{F-32}{180}

Now by putting the values

\dfrac{K-273}{100}=\dfrac{F-32}{180}

\dfrac{0-273}{100}=\dfrac{F-32}{180}

So F= - 459.67°F

So we can say that 0 K is equal to  - 459.67°F.

So the our option e is correct.

3 0
4 years ago
I need help fast! !!!
I am Lyosha [343]
I think it would be at 3 or 6 but I would go with 3 not really sure tho
3 0
3 years ago
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