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erma4kov [3.2K]
3 years ago
6

Suppose that an object is moving with constant nonzero acceleration. Which of the following is an accurate statement concerning

its motion? (a)- In equal times its speed changes by equal amounts.(b)-In equal times its velocity changes by equal amounts. (c)- In equal times it moves equal distances. (d)- A graph of its position as a function of time has a constant slope. (e)- A graph of its velocity as a function of time is a horizontal line.
Physics
1 answer:
Wittaler [7]3 years ago
8 0

Answer: The right answer is b)

Explanation:

By definition, acceleration is the change in velocity (in module or direction) over a given time interval, as follows:

a = (v-v₀) / (t-t₀)

If we take t₀ = 0 (this is completely arbitrary), we can rewrite the equation above, as follows:

v = v₀ + at

We can recognize this function as a linear one, where a represents the slope of the line.

If a is constant, this means that the relationship between the change in velocity and the change in time remains constant, in other words, in equal times, its velocity changes in an equal amount.

Let's suppose that a = 10 m/s/s. (Usually written as 10 m/s²).

This is telling us that each second, the velocity increases 10 m/s.

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One example of current electricity are transmission lines. These bring electricity from power stations to individual houses.
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Two or more explanatory variables that are not separated best describes which of the choices below?
OverLord2011 [107]
"Confounding variable" is the choice among the following choices given in the question that best describes two <span>or more explanatory variables that are not separated. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has come to your help.</span>
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3 years ago
A point charge q1 = -5.7 μC is located at the center of a thick conducting spherical shell of inner radius a = 7.4 cm and outer
olga55 [171]

Answer: a) see attach file; b) E=0;  c)E=-1.65* 10^6 N/C

Explanation: In order to solve this problem we have to use the gaussian law which is given by:

∫E*dr=Q inside/εo

E for r=8 cm is located inside the conducting shell so E=0.

For r=13 cm we have to use above gaussian law considering the total charge inside a gaussian surface with radius equal to 0.13 m. ( see attach)

4 0
3 years ago
A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in
xz_007 [3.2K]
The answer:
the full question is as follow:
 <span>A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in Figure below , where A = 4.90 km and θC = 15°. He then correctly calculates the length and orientation of the fourth side D. What is the magnitude and direction of vector D? 

As shown in the figure, 
A + B + C + D = 0, so to find the </span>magnitude and direction of vector D, we should follow the following method:
 D = 0 - (A + B + C) , 
let  W = - (A + B + C), so the magnitude and direction of vector D is the same of the vector W characteristics

Magnitude
 A + B + C = <span> (4.90cos7.5 - 2.48sin16 - 3.02cos15)I</span>
<span>+ (-4.9sin7.5 + 2.48cos16 + 3.02sin15)J
</span>= 1.25I +2.53J
the magnitude of W= abs value of (A + B + C) = sqrt (1.25² + 2.53²)
= 2.82
 
the direction of D can be found by using Dx and Dy value
we know that     tan<span>θo = Dx / Dy = 1.25 / 2.53 =0.49
</span>tanθo =0.49 it implies θo = arctan 0.49 = 26.02°

direction is 26.02°

4 0
3 years ago
Two objects, M = 15.3 ks and m = 8.29 kg are connected with an ideal string and suspended by a pulley (which rotates with no fri
Scilla [17]

Answer:

(a) 7 m/s

(b) 931 rad/s

(c) 0.716 s

Explanation:

Gravity would be exerting on the 2 masses

G_1 = Mg = 15.3*9.81 = 150.093N

G_2 = mg = 8.29*9.81= 81.32N

Since heavier, mass 1 (M) would be the one pulling down, while mass 2 is being pulled up.

So the net force on mass 1 is

F = G_1 - G_2 = 68.77N

This force would generate torque on the solid pulley

T = FR = 68.77 * 0.0075 = 0.5158 Nm

We can also calculate the pulley moments of inertia, with it being solid

I = 0.5MpR^2 = 0.5*14.1*0.0075^2 = 0.000396563kgm^2

From there we can calculate the angular acceleration of the pulley, which generates the entire system motion

\alpha = \frac{T}{I} = \frac{0.5158}{0.000396563} = 1300.58 rad/s^2

Since the system is moved by a distance of d = 2.5m, the pulley would have turn an angle of

\theta = \frac{d}{R} = \frac{2.5}{0.0075} = 333 rad

(c)The time it takes to get to this distance is

\theta = \frac{\alpha t^2}{2}

t^2 = \frac{2\theta}{\alpha} = \frac{2*333}{1300.58} =0.513

t = \sqrt{0.513} = 0.716s

(b)The final angular speed of the disk is

\omega = \alpha t = 1300.58*0.716 = 931 rad/s

(a) And so the perimeter speed of the pulley, which is also speed of mass 1 when it comes to d = 2.5 m is

v = \omega R = 931*0.0075 \approx 7m/s

5 0
3 years ago
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