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3 years ago

As a skateboarder moves downhill, some of the energy of the skateboarder is

Physics

2 answers:

Sonja [21]3 years ago

6 0

As the skateboard rolls down the ramp it loses potential energy and gains kinetic energy.

Elodia [21]3 years ago

5 0

Answer:

D) kinetic and some potential.

Explanation:

As the skateboard moves it gains kinetic energy and losses some potential energy, so I would say that it has more kinetic energy than potential energy, but it still has both.

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Two identical bodies are sliding toward each other on a frictionless surface. One moves at 1 m/s and the other at 2 m/s. They co

mario62 [17]

Answer:

$V=\dfrac{3}{2}\ m/s$

Explanation:

Two identical bodies are sliding toward each other on a frictionless surface.

Initial speed of body 1, m₁ = 1 m/s

Initial speed of body 2, m₂ = 2 m/s

They collide and stick.

We need to find the speed of the combined mass. Let V is the speed of the combined mass.

Using the conservation of momentum.

$m_1u_1+m_2u_2=V(m_1+m_2)$

We have, m₁ = m₂ = m

$m\times 1+m\times 2=(m+m)V\\\\m+2m=2m\times V\\\\3m=2mV\\\\V=\dfrac{3}{2}\ m/s$

So, the speed of the combined mass is $\dfrac{3}{2}\ m/s$ .

6 0

3 years ago

Two 30 uC charges lie on the x-axis, one at the origin and the other at 9 m. A third point is located at 27 m. What is the poten

alukav5142 [94]

Answer:

25000 V

Explanation:

The formula for potential is

V = Kq/r

Potential at B due to the charge placed at origin O

V1 = K q / OB

$V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}$

V1 = 10000 V

Potential at B due to the charge placed at A

V2 = K q / AB

$V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}$

V2 = 15000 V

Total potential at B

V = V1 + V2 = 10000 + 15000 = 25000 V

4 0

3 years ago

If you push a 4-kg mass...

Lena [83]

Answer:

Explanation:

F = ma , a = F/m

a1 = F/10 and a2 = F/4

Since Force is constant, a2 will we greater than a1

4 0

3 years ago

2. Connect concepts on the left with a description on the right.

Nuetrik [128]

plzzz explain me your questions

8 0

3 years ago

a string with fixed ends is made to go into standing wave patterns. at a given tension, the lowest frequency for which a certain

lakkis [162]

Answer:

700 hz

Explanation:

3 0

3 years ago