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3 years ago

Eva marked 18% of the emails in her inbox at important.if she has 150 emails in her inbox, how many did ahe mark as important?

Mathematics

1 answer:

Natalija [7]3 years ago

5 0

You would take .18 and multiply it by your total 150 and get 27, so your answer is 27 emails

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nikklg [1K]

The answer is 31.626

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3 years ago

At a football stadium, 10% of the fans in attendance were teenagers. If there were 30 teenagers at the football stadium, what wa

JulijaS [17]

Answer:

i believe the answer to this is a total of 300 people because you multiply the ten percent into the 30 people which factors out some numerical values, so then your answer as i just said is 300 people in total attended the game.

Step-by-step explanation:

8 0

2 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Is this table linear or nonlinear?

olchik [2.2K]

Answer:

Linear (❁´◡`❁)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Jackie is taking a week-long football class. The first day, she gains 6 yards on her only possession of the football. On the sec

Veronika [31]

Answer:

Step-by-step explanation:

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3 years ago