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Setler [38]
2 years ago
9

Jason left a bin outside in his garden to collect rainwater. He notices that 1 over 5 gallon of water fills 2 over 3 of the bin.

Write and solve an equation to find the amount of water that will fill the entire bin. Show your work. Explain your answer in words.
Mathematics
2 answers:
sergiy2304 [10]2 years ago
8 0

Answer: 3/10

Step-by-step explanation: (1/5) gallon / (2/3) bin = x gallons / 1 bin cross-multiply

1/5 = (2/3)x multiply both sides by the reciprocal of 2/3 = 3/2

(3/2) (1/5) = x = 3/10 gallons fills the entire bin

Look at it this way......each 1/10 of a gallon fills 1/3 of the bin......so 3(1/10) gallons fills 3(1/3)bins....or

3/10 gallons fills a whole bin...

dusya [7]2 years ago
6 0

Answer:

We can set this up as a proportion

(1/5) gallon / (2/3) bin = x gallons / 1 bin cross-multiply

1/5 = (2/3)x multiply both sides by the reciprocal of 2/3 = 3/2

(3/2) (1/5) = x = 3/10 gallons fills the entire bin

Look at it this way......each 1/10 of a gallon fills 1/3 of the bin......so 3(1/10) gallons fills 3(1/3)bins....or

3/10 galons fills a whole bin....

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Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
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Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

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