Https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:sequences/x2f8bb11595b61c86:constructing-arithmetic-sequences/v/finding-the-100th-term-in-a-sequence
(y+1)=3(x-1) is the answer to your problem
There are 6 letters, each different
Before MOTHER, words from E , H will come
Words from E = 5! (there are 5 letters to arrange)
Words from H = 5!( there are 5 letters to arrange)
Now words starting by M will come.
First ME will have = 4! (as 4 letters will be arranged)
Then MH = 4!
Now words with MO<span>
</span><span>First words starting with MOE... =3!
And words starting with MOH... =3!
the words starting with MOR... =3!
Now, words starting from MOT will come
words starting with MOTE.. = 2!
then after words starting from MOTH will come and first word will MOTHER
so, total no. of words before MOTHER = 5! + 5! + 2* 4! + 3 * 3!
= 120 +120 + 48 + 18
= 306
so, rank of MOTHER = 307</span>
Answer:
1144 o 286
Step-by-step explanation:
Si pregunta por la cantidad de personas que se pesaron, la respuesta es (8/10) * (1430) = 8 * 143 = 1144.
Si desea saber cuántas personas no se pesaron, la respuesta es 1430* (2/10) = 286
Answer: 475 adults paid admission
Step-by-step explanation:
1.50c+4a=5050 (1.50 per child and 4 per adult)
1.50(2100)+4c=5050 (2100 children times 1.5 each)
3130+4a=5050
4a=1900
a=475
