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uysha [10]
3 years ago
5

Jackie is taking a week-long football class. The first day, she gains 6 yards on her only possession of the football. On the sec

ond day, she quarterbacks for 3 plays and gains 6 yards on each play. What is the total number of yards Jackie gained?
Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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The sixth grade art students are making a mosaic using tiles in shapes of right triangles. Each tiles has the leg measures of 5.
Drupady [299]

Given:

Each right triangular tiles has the leg measures of 5.2 cm and 6 cm.

There are 150 tiles in the mosaic.

To find:

The area of the mosaic.

Solution:

We know that, the area of a triangle is:

A=\dfrac{1}{2}\times Base\times height

So, the area of Each right triangular tile is:

A=\dfrac{1}{2}\times 5.2\times 6

A=\dfrac{1}{2}\times 31.2

A=15.6

There are 150 tiles in the mosaic. So, the area of the mosaic is:

Area=15.6\times 150

Area=2340

Therefore, the total area of the mosaic is 2340 cm ².

5 0
3 years ago
Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the sec
Delvig [45]

Answer:

I believe the red one is the first image then the blue then the green because they show the prime sign

Step-by-step explanation:

4 0
3 years ago
Identify the location of the point (-3, -2).<br><br> A. P<br> B. Q<br> C. R<br> D. S
docker41 [41]

Answer:

You haven't given a picture of the graph dear.

The point (-3,-2) lies in the third quadrant.

8 0
3 years ago
How do you write 55 another way
CaHeK987 [17]
It can also be written as fifty-five.
7 0
3 years ago
Internet company Gurgle is carrying out testing on the efficiency of its search engine. A sample of 31 searches have been carrie
Mrac [35]

Answer:

d. Approximate the standard normal distribution with the Student's t distribution

(0.2199 ; 0.2327)

Step-by-step explanation:

Given that :

Sample size, n = 31

Sample mean, xbar = 0.2258

Sample standard deviation, s = 0.0188

Confidence interval (C. I) :

xbar ± margin of error

Margin of Error : Tcritical * s/sqrt(n)

Degree of freedom, df = n - 1 = 31 - 1 = 30

Tcritical value :

T0.05/2, 30 = 2.042

Margin of Error = 2.042 * 0.0188/sqrt(31)

Margin of Error = 0.0068949

C. I = 0.2258 ± 0.0068949

Lower boundary : (0.2258 - 0.006895) = 0.2189

Upper boundary : (0.2258 - 0.006895) = 0.2327

(0.2199 ; 0.2327)

3 0
3 years ago
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