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4 years ago

A linear enzyme is formed by four alpha and two beta protein subunits. How manydifferent arrangements are there?

Mathematics

1 answer:

tankabanditka [31]4 years ago

6 0

Answer:

Step-by-step explanation:

We are given that

Number of alpha protein subunits=4

Number of beta protein subunits=2

Total number of protein sub-units=2+4=6

We have to find the number of different arrangements are there.

When r identical letters and y identical letters and total object are n then arrangements are

$\frac{n!}{r!x!}$

n=6,r=2,x=4

By using the formula

Then, we get

Number of different arrangements = $\frac{6!}{2!4!}$

Number of different arrangements= $\frac{6\times 5\times 4!}{2\times 1\times 4!}$

Number of different arrangements=15

Hence, different arrangements are there= 15

You might be interested in

Factor the expressions and write the equivalent expression 1) 20h-5 2)15r+35 3)-4p+10

MrRa [10]

Answer:

1) 5 ( 4h - 1 )

2) 5 ( 3r + 7 )

3) 2( -2p +5 )

Step-by-step explanation:

For no. 1 you have to find a common factor (a number that divides into both 20 and 5) which is 5 because 20 divided by 5 is 4 and 5 divided by 5 is 1. so you have to do 20h divided by 5 which is 4h (don't forget the h ! ) and you do -5 divided by 1 which is -1. Remember when you do any multiplying or dividing questions with negatives and positives :

minus + minus = minus (-5*-6 = -30)

positive + positive = positive (5*6 = 30) * equals multiplacation by the way

minus + positive = minus (-5*6 = -30)

positive + minus = minus (5*-6 = -30)

hope this helped xx

8 0

3 years ago

Dee saves $20 a week for 10 weeks. during her 5-day vacation, she plans to spend $6.75 each day for snacks. which expression sho

QveST [7]

$20 a week for 10 weeks is:

20*10 = $200

She spends $6.75 each day for 5 days:

6.75*5 = $33.75.

Lets subtract her spending from her savings to find out how much she has left:

$200-$33.75 = $166.25

4 0

4 years ago

Read 2 more answers

A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and r

dsp73

Answer:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

Now we can find the degrees of freedom:

$df=n-1=80-1=79$

Now we can calculate the p value with the alternative hypothesis using the following probability:

$p_v =P(t_{(79)}>2.236)=0.0141$

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if shoppers participating in the loyalty program spent more on average than typical shoppers (120) , the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$