1. First consider the unknown original price as 'x'.
2. Then consider the rate of discount.
3. To find the actual discount, multiply the discount rate by the original amount 'x'.
4. To find the sale price, subtract the actual discount from the original amount 'x' and equate this to given sale price.
Answer:
x + 2 ( x - 20 )( 4 ) = -70
Step-by-step explanation:
hope this helps. . .<3
F(x) + k - Moves the graph k units up.
k f(x) stretches the graph parallel to y-axis by a facor k
f (kx) stretches the graph by a factor 1/k parallel to x-axis
f(x + k) moves the graph 3 units to the left.
For k negative the first one moves it k units down
for second transform negative does same transfoormation but also reflects the graph in the x axis
For the third transform negative k :- same as above but also reflects in y axis
4th transform - negative k moves graph k units to the right
Answer:
Approximately 11 inches
Step-by-step explanation:
Answer:
a = 1565217.39 ft / s ^ 2
t = 0.001725 seconds
Step-by-step explanation:
The first thing is to use the same system of units therefore we will pass the 28 inches to feet, like this:
28 in * (1 ft / 12 in) = 2.33 ft
Now yes, we can continue, we have the following data:
vi = 0
vf = 2700 ft / s
the equations in this case are as follows:
vf = vi + a * t
vf = a * t
rearranging for a
a = vf / t (1)
now with the position equation we know that:
x = vi * t + (a * t ^ 2) / 2
x = (a * t ^ 2) / 2 (2)
now replacing (1) in (2), we are left with:
x = (vf / t) * (t ^ 2) / 2
knowing that x would be 2.33 ft, which is when the cannonball exits the cannon.
2.33 = 2700 * t / 2
t = 2.33 * 2/2700 = 0.001725 seconds.
and now replace in (1)
a = vf / t = 2700 / 0.001725 = 1565217.39 ft / s ^ 2
