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Brrunno [24]
3 years ago
13

Identify the vertex y=x^2-2x-3

Mathematics
1 answer:
Ulleksa [173]3 years ago
7 0

Answer:

<em>The vertex is located at (1,-4)</em>

Step-by-step explanation:

<u>Equation of the Quadratic Function</u>

The vertex form of the quadratic function has the following equation:

y=a(x-h)^2+k

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We have the following quadratic equation and we need to express it in vertex form. Thus, we need to complete the squares:

y=x^2-2x-3

Adding and subtracting 1:

y=x^2-2x+1-3-1

The first three terms are the square of a binomial:

y=(x-1)^2-4

Comparing to the vertex form of a quadratic equation, the vertex is at (1,-4).

The vertex is located at (1,-4)

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