All categories

2 years ago

Find the 8th term of the G.P 9,3,1,

Mathematics

1 answer:

son4ous [18]2 years ago

5 0

Answer:

a=9 , d=6 n=8

a+(n-1)d = an

9+(8-1)6 = an

9+7×6 = an

9+42 = an

51 = an

You might be interested in

Distribute and Combine Like Terms. 2(x + 7) - 2x

vodomira [7]

Answer:

Step-by-step explanation:

You just multiply 2 to (x + 7) which gets you 2x + 14 and then subtract 2x from 2x seeing as they are like terms and you end up with 14.

6 0

3 years ago

Read 2 more answers

The length of two sides of triangular field are 16 m and 19m . The perimeter of rectangle is 50 cm find the third side?

Ivahew [28]

50 - (16 + 19)

= 50 - 35

= 15m

5 0

3 years ago

What is center: (-4,-12) Radius: 4 ?

netineya [11]

Answer:

have a great day ❤️❤️☺️

3 0

2 years ago

Read 2 more answers

the grid below is made up of squares with sides of 1cm draw a rectangle with an area of 12 cm squared

Ann [662]

Answer:

6 is length and 2 is width.

4 0

2 years ago

MODELING WITH MATHEMATICS A farmer plants a garden that contains corn and pumpkins. The total area (in square

laiz [17]

Answer:

The equation in standard form that models area of pumpkins is:

$A_p = A_G - A_c$

and the area is: $x^2+8x+2$

Step-by-step explanation:

Given that the garden has corn and pumpkins

The expressions are:

Total area of garden: $A_G = 2x^2+5x+4$

Area of Corn: $A_c = x^2-3x+2$

Area of Pumpkins: $A_p = ?$

The sum of areas of corn and pumpkins is the total area of the garden.

It can be expressed mathematically as:

$A_G = A_c+A_p$

If we have to find the area of pumpkins,

$A_p = A_G - A_c$

Putting the values

$A_p = (2x^2+5x+4) - (x^2-3x+2)\\A_p = 2x^2+5x+4-x^2+3x-2\\A_p = 2x^2-x^2+5x+3x+4-2\\A_p = x^2+8x+2$

The equation in standard form that models area of pumpkins is:

$A_p = A_G - A_c$

and the area is: $x^2+8x+2$

3 0

2 years ago

Find the 8th term of the G.P 9,3,1,​

Find the 8th term of the G.P 9,3,1,