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Kisachek [45]
3 years ago
14

Is berkelium flammable

Chemistry
2 answers:
dusya [7]3 years ago
8 0
Yes berkelium is highly flammable
Brrunno [24]3 years ago
4 0
Yes. Berkelium is flammable
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How many sulfur atoms are there in 3.90 mol of sulfur?
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 <span>In a mole of anything, there are 6.023 x 10^23 units. So, in 3.9 moles of sulfur, there are 3.9 * 6.023 x 10^23 = 23 x 10^23 = 2.3 x 10^24 atoms (keeping only 2 sig figs).  Hope I help!!
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Support a scientist doing and experiment in nuclear fusion starts out with twelve atoms how many atoms will most likely results
vlada-n [284]
What context do they ask you?
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Louis and Keisha each dropped stones from different heights onto pieces of clay to see how much the clay would be compacted. Lou
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Yes. it was less clay which causes less area for impact
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3 years ago
A Rolaids tablet contains calcium for neutralizing stomach acid. if a Rolaids tablet neutralizes 24.65ml of 0.547m hydrochloric
Lelu [443]

There are 674 mg of calcium carbonate in a Rolaids tablet

<h3>Further explanation</h3>

Reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ +H₂O

V HCl = 24.65 ml

M HCl = 0.547

mol HCl :

\tt 24.65\times 0.547=13.48~mlmol

ratio mol CaCO₃ : HCl = 1 : 2, so mol CaCO₃ :

\tt \dfrac{1}{2}\times 13.48=6.74~mlmol=6.74\times 10^{-3}~mol

mass of CaCO₃ (MW=100~g/mol) :

\tt 6.74\times 10^{-3}\times 100=0.674~g=674~mg

4 0
3 years ago
The vapor pressure of pure pentane and pure hexane are 425 torr and 151 torr respectively. equal moles of pentane and hexane are
nadezda [96]

The mole fraction of pentane in the vapor is 0.291

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Using the formula for vapour pressure,

vapour pressure = P^{}°_{hex} × X_{hex} + P^{}°_{pen} × X_{pen}

vapour pressure = 151 ×  (1-X_{pen}) + 425 × X_{pen}

240 = 151 - 151X_{pen} + 425X_{pen}

240 - 151 = -  151X_{pen} + 425 X_{pen}

89 = 274 X_{pen}

\frac{89}{274} = X_{pen}

0.291 = X_{pen}

Therefore,  the mole fraction of pentane in the vapor is 0.291

Learn more about vapour pressure here;

brainly.com/question/25699778

#SPJ4

3 0
2 years ago
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