Average atomic mass is the weighted average atomic masses with regard to the relative abundance of the isotopes
average atomic mass of Li = relative abundance of Li-6 x mass of Li-6 + relative abundance of Li-7 x mass of Li-7
average atomic mass of Li = (7.42% x 6.0151 a.m.u) + (92.58% x 7.0160 a.m.u)
= 0.446 + 6.495
= 6.941 amu
average atomic mass of Li is 6.941 amu
When a monovalent cation X binds to a divalent anion Y, a compound with the formula 
would be formed.
A monovalent cation is an atom that has lost an electron. Hence, such cation has a single positive charge. A monovalent cation X will, thus, be 
A divalent anion is an atom that has gained two electrons. Such anion has 2 negative charge. Thus, divalent Y would be 
Since Y is a divalent anion, it requires 2 electrons in order to successfully bind with another charged atom, a cation to be specific. Thus, two of would be required to successfully bind
+ + ---->
More on the chemical formula can be found here: brainly.com/question/16741890
Answer: A strong acid like HCl dissociates completely in an aqueous solution.
By definition a strong acid is that that dissociates completely in aqueous solutions. That means that all the molecules of the acid will be inoized into hydronium cation (H3O+) and anion (the negative radical).
For expample, HCl is a strong acid because
HCl + H2O----> H3O(+) + Cl-
The forwar arrow indicates that all the molecules of HCl reacted with the water for form the ions.
Gravitational, elastic, and chemical are three forms of potential energy.
The dilution factor of the unknown sample is 10. The dilution factor of a solution refers to the ratio of the final volume of the now diluted solution to the initial volume of the of the initial concentrated solution.
Mathematically;
The dilution factor is given by the formula;
Dilution factor = Final volume of the now diluted solution/ Initial volume of more concentrated solution
Final volume of the now diluted solution = 100.0 ml
Initial volume of more concentrated solution = 10.00 ml
Dilution factor = 100.0 ml/10.00 ml
Dilution factor = 10
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