The answer is 0.154 m
Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒ V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³
Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625 / 0.405
d = 0.154 m
Answer:
B
Step-by-step explanation:
Equation of line 1:
Choose two points : (-1, 0) & (0,2)
y -intercept = b = 2
y = mx+ 2
Plugin the values of the points ( -1 , 0) in the above equation
0 = -1m + 2
-2 = -m
m = 2
Equation of line 1 : y = 2x + 2
Equation of line 2:
(5,0) & (0,5)
y-intercept = b = 5
y = mx +b
y = mx + 5
Plugin the value of points (5 , 0) in the above equation
0 = 5m + 5
-5 = 5m
-5/5 = m
m = -1
Equation of line 2: y = -x + 5
Conclusion: 2x + 2 = -x + 5
the answer is 72
let me know if you need an explanation
Answer:
volume = 240 in.^2
240 times 1/2 = 240/2
240/2 = 120
Step-by-step explanation:
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period.
Let's say 40 days period = 100%.
Then what's 28 days?
</span>
So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>
The final answer is B. 70%.
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