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svlad2 [7]
3 years ago
13

4-(11/3)/4-(2/3) how do i solve this

Mathematics
1 answer:
kirill [66]3 years ago
6 0

Answer: 0.1 or \frac{1}{10}

Step-by-step explanation:

\frac{4-\frac{11}{3} }{4-\frac{2}{3} }

= \frac{1}{10}

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Multiple Choice
mihalych1998 [28]

Answer:

D is correct

Step-by-step explanation:

A graph of that sort will make a perfectly mirrored "V" shape, and with no offset, the bottom point will be on the y axis.  This means that the first equation will intercept the y axis at zero, the second will intercept the y-axis at -15.

"A" may seem correct also, as the second graph will intercept the x-axis at -15, but it is not complete, as it will intercept that axis at +15 as well.

7 0
2 years ago
A factor tree for 61 that is not nothing
ddd [48]
False because the factor tree for 61 is 1 and 61

5 0
3 years ago
Factor completely 3x2 - 21.
VMariaS [17]
3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go.  But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:

3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.
6 0
3 years ago
Read 2 more answers
According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers
postnew [5]

Answer:

Probability that a smoker has lung disease = 0.2132

Step-by-step explanation:

Let L = event that % of population having lung disease, P(L) = 0.07

So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93

S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

                        P(S/L) = \frac{P(S\bigcap L)}{P(L)}  

                        P(S\bigcap L) = P(S/L) * P(L)

                                      = 0.90 * 0.07 = 0.063

So,  P(S\bigcap L) = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

      P(L/S) = \frac{P(S\bigcap L)}{P(S)}

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

       = 0.90 * 0.07 + 0.25 * 0.93 = 0.2955

Therefore, P(L/S) = \frac{0.063}{0.2955} = 0.2132

Hence, probability that a smoker has lung disease is 0.2132 .

7 0
3 years ago
Evaluate the expression.<br><br> (1.5)2(1.5)<br> −2⋅(1.5)4
aleksklad [387]
Is this (1.5)2(1.5) / -2(1.5)4?  or is it (1.5)2(1.5) - 2(1.5)4?

First option:
4.5/-12 = -0.375

Second option
4.5-12 = -7.5
8 0
3 years ago
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