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Nonamiya [84]
3 years ago
11

A school is selling tickets to a choral performance. On the first day, the school sold 6 adult tickets and 6 child tickets for $

102. The school took in $96 on the second day selling 12 adult tickets and 3 child tickets. How much does each ticket cost ?
Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

adult $5

child $12

Step-by-step explanation:

make the adult as x and child as y.

this will makes 6x + 6y = 102

12x + 3y = 96

solve it and the answer comes out.

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I NEED HELP ASAP PLEASE!! I WILL AWARD BRAINLIEST
Irina-Kira [14]

9514 1404 393

Answer:

  • x ≥ 7
  • 54 -6m
  • y -x

Step-by-step explanation:

You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.

108. |x -7| = x -7 . . . . . true for x-7≥0

  x ≥ 7 . . . . makes the statement true

__

1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:

  54 -6m . . . . . simplified form for m < 9

__

1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive

6 0
3 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
How do you solve 8x-7= 3x 9?
gtnhenbr [62]
8x - 7 = 3x + 9
8x - 3x = 9 + 7
5x = 16
x = 16/5 = 3 1/5
3 0
3 years ago
the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt
zhuklara [117]
Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when 
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21

7 0
3 years ago
A new cell phone was $625 but it was reduced to $500. What was the percent of decrease?
zepelin [54]

Answer:

80%

Step-by-step explanation:

To find percent decrease (new amount/original amount)*100

(500/625)*100

=80

--

to check

625*.80  

=500

or

625*80%

=500

4 0
3 years ago
Read 2 more answers
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