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Nonamiya [84]
3 years ago
11

A school is selling tickets to a choral performance. On the first day, the school sold 6 adult tickets and 6 child tickets for $

102. The school took in $96 on the second day selling 12 adult tickets and 3 child tickets. How much does each ticket cost ?
Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

adult $5

child $12

Step-by-step explanation:

make the adult as x and child as y.

this will makes 6x + 6y = 102

12x + 3y = 96

solve it and the answer comes out.

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Tourists were on a hiking trip for three days. On the first day, they hiked 1/8 of the trail. On the second day they hiked 4/7 o
kramer

Answer:

64/7 i think

Step-by-step explanation:

whole trip ---- x km


day1 , hiked 1/8 of train, leaving (7/8)x

day 2 , hiked 4/7 of (7/8)x leaving

(3/7)(7/8)x or (3/8)x to be hiked

day3 :

(1/3)(3/8)x + 8 = x

x/8 + 8 = x

times 8

x + 64 = 8x

7x = 64


the trail is 64/7 km


check:

day 1 they hiked (1/8)(64/7)

leaving (7/8)(64/7) = 8 km

day2, hiked 4/7 of remaining, leaving

(3/7)(8) or 24/7 km

day 3

(1/3)(24/7) + 8

= 64/7

yeahhh!

8 0
4 years ago
Read 2 more answers
chris is considering living at home for his freshman year of college in order to take some of his basic classes. according to th
Diano4ka-milaya [45]

Answer:

He would save 9,730$.

Step-by-step explanation:

At the 2y college, add the numbers and you'd get 6,400.

At the 4y college, you'd get 16,130.

You'd subtract the two to get 9,730.

3 0
3 years ago
Please help fast it’s a test
photoshop1234 [79]

Answer:

The first box is 8 and the second box is 96

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
Read 2 more answers
6 - 2 to the third power + (-9 + 5) · 2.
Alexxx [7]

Answer:

40

Step-by-step explanation:

6- 2 = 4 / 4*4*4 = 32

-9+5=4/4*2=8


32 + 8 = 40

Could really use brainliest if thif helps

5 0
3 years ago
Read 2 more answers
If ab = 9 and a² + b² = 81, then (a+b)² = ?​
Andre45 [30]

Answer:

99

Step-by-step explanation:

Through some clever algebra, we can combine our first two equations using the fact that

(a+b)^2=a^2+2ab+b^2

We have the a² and the b² in the equation a^2+b^2=81, and we <em>almost </em>have a 2ab in the equation ab=9. To get that 2ab, we can simply double both sides of the first equation to get 2ab=18. From there, we'll add the first two equations together, giving us the summed equation

a^2+b^2+2ab=81+18\\a^2+2ab+b^2=99

And since (a+b)^2=a^2+2ab+b^2, we can equivalently say that

(a+b)^2=99

5 0
3 years ago
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