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Nonamiya [84]
3 years ago
11

A school is selling tickets to a choral performance. On the first day, the school sold 6 adult tickets and 6 child tickets for $

102. The school took in $96 on the second day selling 12 adult tickets and 3 child tickets. How much does each ticket cost ?
Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

adult $5

child $12

Step-by-step explanation:

make the adult as x and child as y.

this will makes 6x + 6y = 102

12x + 3y = 96

solve it and the answer comes out.

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Step-by-step explanation:

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3 years ago
Solve for X<br> 9x + 2 = 3<br> Give your answer as a fraction in its simplest form.
kati45 [8]

Answer:x=1/9

Step-by-step explanation:

1. subtract 2 from both sides

9x+2-2=3-2

2.simplify

9x=1

3.Divide both sides by 9

9x/9=1/9

4.simplify

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4 0
3 years ago
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Wyatt has 3 times as many baseballs as golf balls. He has 5 fewer tennis balls than baseballs. Wyatt has 4 golf balls. How many
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Since he has 4 golf balls, he has 12 baseballs because 4 times 3 is 12. Then you do 12 - 5 = 7 tennis balls.
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3 years ago
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If Sheila paid $797.50 in interest on a 5 year loan of $5,800 for her first car, what was the interest rate? (Make sure you’ve c
allochka39001 [22]
In calculating the interest on a car we have a formula

(interest rate/number of payments) x loan principal = interest.
 
Since, we have:
Interest rate = ?
number of payments = 60 ( 5 year loan x 12 months)
loan principal = 5800
interest = 797.50

We need to derive a formula to find the IR(interest rate)

(interest rate/60) x 5800 = 797.50
IR (5800) / 60 = 797.50
IR (5800) = 797.50 (60)
IR (5800) = 47850
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7 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
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