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3 years ago

UGH these math problems tho please help!

Mathematics

2 answers:

Dovator [93]3 years ago

7 0

Answer:

#6 would be 15/7

#7 would be 4/90

#8 would be 17/12

i can't see number 9

#11 would be 65/15 or 4.3333333

31 + 34

Step-by-step explanation:

aleksley [76]3 years ago

5 0

Answer:

Answer:

#6 would be 15/7

#7 would be 4/90

#8 would be 17/12

i can't see number 9

#11 would be 65/15 or 4.3333333

31 + 34

Step-by-step explanation:

So True i think

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HELP ASAP WILL GIVE BRAINLIEST

Alona [7]

Answer:

y=2 $x^{2}$ -7x-4

three linear equations

c=-4 ;4a+b=1 ; 9=a-b

Step-by-step explanation:

Simply assume a standard parabola equation y=a $x^{2}$ +bx +c

(here a, b, c are three independent variables)

Three coordinates as shown in graph are (0,4), (4,0) ,(-1,5)

Now put these points in the equation of parabola and get three linear equations.

[1] c=-4

[2] 4a+b=1

[3] 9=a-b

Now substitute value of a from equation 2 into 3 in terms of b

a= $\frac{1-b}{4}$

9= $\frac{1-b}{4}$ -b

b=-7

a=2

y=2 $x^{2}$ -7x-4

6 0

3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$