Look at the image below where I labeled the sides
To solve this you must use Pythagorean theorem:
a and b are the legs (the sides that form a perpendicular/right angle)
c is the hypotenuse (the side opposite the right angle)
In this case...
a = 4
b = 6
c = unknown
^^^Plug these numbers into the theorem
simplify
16 + 36 =
52 =
To remove the square from x take the square root of both sides to get you...
√52 = x
^^^Unsimplified radical
2√13
^^^Simplified radical
7.21
^^^Rounded to hundedths
Hope this helped!
~Just a girl in love with Shawn Mendes
The answer 274 because anything divided by one is itself
Answer:
( - infinity, -3 ] [ -2, infinity )
square bracket means it includes the end point.
Step-by-step explanation:
(-∞, -3]U [-2,∞)
Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that 
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-

Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31