All categories

3 years ago

Can someone please explain how to do this? Geometry EOC's are tomorrow and I have to know this stuff so please answer quickly.

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

8 0

A rule of Polygons is that the sum of the exterior angles must equal 360.
Remember that for your testing.
A polygon is where all sides equal the same amount, in your case, 18 degrees.
So divide 360 by 16, equalling D.20
Good Luck!

Dmitry_Shevchenko [17]3 years ago

8 0

3.
we can solve it

draw a point for the center
draw lines from the center to each vertex
you get lots of triangles

see the diagram so it won't be confusing an since I will be refering to stuff in there

striahge line=180
so
18+x+x=180
minus 18
2x=162
divide 2
x=81
now we know 2 interior angles
x and y=81
angles ina triangle add to 180
therefor
x+y+z=180
81+81+z=180
162+z=180
minus 162
z=18

all central angles add up to 360
how man y are there?
18 times how many=360
divide both sidess by 18
how many angles=20
20 central angles=20 sides

4.

we can compare using side to angle ratios
since 9=9 and they share a side, the sides PQ and SR and congruent and PS is congruent to PS
therfor the only different side is QS and PR

ratio is the angles
QS:PR=63:105=3:5

they are in ratio 3:5

You might be interested in

Tom had eight hundred fifty-three pieces of candy. If he wants to split

solniwko [45]

Answer:

35 more pieces

Step-by-step explanation:

888 - 853 = 35

Hope that helps! :) <3

3 0

3 years ago

What is the slope of the graph of 4 x + 8 y = 11?

Karolina [17]

Answer:

B -1/2

Step-by-step explanation:

4x+8y = 11

We need to get the equation in the slope intercept form

y = mx+b where m is the slope and b is the y intercept

Subtract 4x from each side

4x-4x+8y = -4x+11

8y = -4x+11

Divide by 8

8y/8 = -4x/8 +11/8

y = -1/2x +11/8

The slope is -1/2 and the y intercept is 11/8

8 0

3 years ago

Read 2 more answers

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

Question 1 of 5

viktelen [127]

Answer:

4 . 4√4 is equal to this expression (256•64)^1/4 .

5 0

3 years ago

Scores on a test have a mean of 70 and q3 is 83. the scores have a distribution that is approximately normal. find p90. (you wil

Hunter-Best [27]

Answer: Q3 represents 75%, meaning a z of ~0.67 80 - 70 is 10, so the standard deviations is ~14.9. 10 / 0.67 = 14.9 now find the z that represents a score of 90 90 - 70 is 20 20 / 14.9 = 1.34 from a z-table, a z of 1.34 represents a probability of ~90.99% meaning that there is about a 9.01% chance of getting a 90 or better.

5 0

4 years ago