Answer: 31 & 42
<u>Step-by-step explanation:</u>
1st #: x
2nd #: x + 11
1st# + 2nd# = sum
x + x + 11 = 73
2x + 11 = 73
2x = 62
x = 31
2nd #: x + 11 = 31 + 11 = 42
Answer B.
∑fx=1637,∑fx
2
=127663,∑f=21
x
ˉ
=Mean=
∑t
∑fx
=77.95
σ
2
=
∑f
∑fx
2
−(
x
ˉ
)
2
=
21
127663
−(77.95)
2
=2.987
σ=1.728
Answer:
91/216
Step-by-step explanation:
The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.
P(at least one 4) = 1 − P(no 4s)
P(at least one 4) = 1 − (5/6)³
P(at least one 4) = 91/216
Alternatively, you can calculate it this way.
The probability of getting a 4 on the first roll is 1/6.
The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.
The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.
The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.
1. 8r + 4 = 10 + 2r
-4 -4
8r = 6 + 2r
-2r -2r
6r = 6
R= 1
2. -2(x + 3) = 4x - 3
-2x - 6 = 4x - 3
+3 +3
-2x -3 = 4x
+2x +2x
-3 = 6x
————-
6 6
-1/2 = x
3. 5 + 3(q - 4) = 2(q + 1)
5 + 3q - 12 = 2q + 2
-7 + 3q = 2q + 2
+7 +7
3q = 2q + 9
-2q -2q
Q = 9
4. 7x - 4 = -2x + 1 + 9x - 5
7x - 4 = 7x - 4
-7x -7x
-4 = -4
+4 +4
0 = 0
Infinite answers
5. 8x + 6 - 9x = 2 - x -15
-x +6 = - 13 - x
+ x +x
6 = -13
No solution
could you further explain?
