Answer:
-4, 0, and 4
Step-by-step explanation:
Answer:
<u>Given function</u>
#15 Find the inverse of h(x)
<u>Substitute x with y and h(x) with x and solve for y:</u>
- x = 2y - 1
- 2y = x + 1
- y = 1/2x + 1/2
<u>The inverse is:</u>
#16 The graph with both lines is attached.
The x- and y-intercepts of both functions have reversed values.
#17 Table of the inverse function will contain same numbers with swapped domain and range.
<u>Initial look is like this:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | | 0 | | 1 | | 2
<u>The rest of the table is filled in by finding the values:</u>
- <u>x | -3 | -2 | -1 | 0 | 1 | 2 | 3</u>
- h⁻¹(x) | -1 | -0.5 | 0 | 0.5 | 1 | 1.5 | 2
Answer:
Step-by-step explanation:
Given
-- degree of freedom
Required
Determine the t-value
The given parameters can be illustrated as follows:
Where
So, we have:
To solve further, we make use of the attached the student's t distribution table.
From the attached table,
The t-value is given at the row with df = 28 and is 3.673900
Hence,
Answer:
3√6
Explanation:
explanation is in the image above
HOPE THIS HELPS PLEASE MARK ME BRAINIEST
<span>y=2\3x-17and 4x-6y=-7 implies - 6y= - 4x -7, and then y= (-4/-6)x +7/6 and so
y=2/3x+7/6
but when we have y=ax+b and y=a'x+b', the two lines are parallels if a=a', in our case 2/3=2/3 the lines are parallel
</span>